状态机和协同程序 [英] State Machines and Coroutines
问题描述
状态机和协同程序
goto上的另一个主题：让我想问一下......本着
状态机和协同程序的精神，这个N00b到C想知道是否
setjmp / longjmp是打破常规的唯一方法;离开
函数并重新进入堆栈状态。
我问这个是因为我只是简单地回顾了这些函数/>
我相信longjmp只返回指定的int。因此我将会天真地假设指针会/可能用于返回或改变
变量。我想我记得有关挥发性
限定词的内容也在使用。
谢谢你，
Deiter
State Machines and Coroutines
The other thread on goto: Lead me to want to ask... In the spirit of
state machines and coroutines, This n00b to C would like to know if
setjmp/longjmp are the only way to break out of a routine; leave the
function and re-enter the stack state.
I ask this because I''ve only briefly, as yet, reviewed these functions
and I believe longjmp will only return a designated int. Therefore I
would naively assume pointers would/could be used to return or alter
variables. I think I remember something mentioned about volatile
qualifiers being used as well.
Thank you,
Deiter
推荐答案
Deiter写道：
Deiter wrote:
状态机和协同程序
其他goto上的帖子：引导我想问......在状态机和协同程序的精神中，这个n00b到C想知道是否
setjmp / longjmp是打破的唯一方法例程;离开
函数并重新进入堆栈状态。
我问这个是因为我只是简单地回顾了这些函数
我相信longjmp只会返回一个指定的int。因此我会天真地假设指针会/可能用于返回或改变变量。我想我记得有关挥发性
限定词的内容也被使用了。
State Machines and Coroutines
The other thread on goto: Lead me to want to ask... In the spirit of
state machines and coroutines, This n00b to C would like to know if
setjmp/longjmp are the only way to break out of a routine; leave the
function and re-enter the stack state.
I ask this because I''ve only briefly, as yet, reviewed these functions
and I believe longjmp will only return a designated int. Therefore I
would naively assume pointers would/could be used to return or alter
variables. I think I remember something mentioned about volatile
qualifiers being used as well.
嗨Deiter，
我不是完全确定你在这里想要做什么，但听起来好像你想要在你到达终点之前退出一个功能吗？
你可以退出具有return（var）语句的任何点的函数。对于
示例，如果您的基金返回一个整数，您可以调用return（0）。
例如
int test_fnc（int input）
{
if（input> = 1）
return（1）;
其他
返回（0）;
}
返回参数后，该函数将从堆栈中删除。 />
希望有所帮助，
Alastair
Hi Deiter,
I''m not entirely sure what you are trying to do here, but it sounds
like you want to exit a function before you have reached the end?
You can exit a function at any point with the return(var) statment. For
example if your fundtion returns an integer you can call return(0).
e.g.
int test_fnc(int input)
{
if (input >= 1)
return (1);
else
return(0);
}
After the return statment the function is removed from the stack.
Hope that helps,
Alastair
Alastair写道：
Alastair wrote:
Deiter写道：
Deiter wrote:
状态机和协同程序
goto上的另一个主题：引导我想问......本着
状态的精神机器和协同程序，这个n00b到C想知道是否
setjmp / longjmp是打破常规的唯一方法;离开
函数并重新进入堆栈状态。
我问这个是因为我只是简单地回顾了这些函数
我相信longjmp只会返回一个指定的int。因此我会天真地假设指针会/可能用于返回或改变变量。我想我还记得有关挥发性
限定词的内容。
State Machines and Coroutines
The other thread on goto: Lead me to want to ask... In the spirit of
state machines and coroutines, This n00b to C would like to know if
setjmp/longjmp are the only way to break out of a routine; leave the
function and re-enter the stack state.
I ask this because I''ve only briefly, as yet, reviewed these functions
and I believe longjmp will only return a designated int. Therefore I
would naively assume pointers would/could be used to return or alter
variables. I think I remember something mentioned about volatile
qualifiers being used as well.
嗨Deiter，
我不完全确定你要做什么在这里，但听起来好像你想在到达终点之前退出一个函数？
你可以在任何时候使用return（var）语句退出函数。对于
示例，如果您的基金返回一个整数，您可以调用return（0）。
int test_fnc（int input）
{
if（输入> = 1）
返回（1）;
返回（0）;
}
返回后的判断该功能从堆栈中删除。
希望有所帮助，
Alastair
Hi Deiter,
I''m not entirely sure what you are trying to do here, but it sounds
like you want to exit a function before you have reached the end?
You can exit a function at any point with the return(var) statment. For
example if your fundtion returns an integer you can call return(0).
e.g.
int test_fnc(int input)
{
if (input >= 1)
return (1);
else
return(0);
}
After the return statment the function is removed from the stack.
Hope that helps,
Alastair
您好，感谢Alastar，但我比我更远了返回。
我相信setjmp允许你放松然后将堆栈放到
中的先前位置，然后调用longjmp。
但我通常对C中的经验如何考虑<感兴趣
高效状态机/协程结构化编程。
谢谢
Hi, thanks Alastar but I''m a bit farther along than returns.
I believe setjmp allows you to "unwind" the stack to a prior position in
the routine when longjmp is then called.
But I''m generally interested in how the experienced in C consider
efficient state machines/coroutine structured programming.
Thanks
>谢谢Alastar但是我回来的时间比我更远。
> Hi, thanks Alastar but I''m a bit farther along than returns.
我相信setjmp可以让你放松。然后，当调用longjmp时，堆栈到了例程中的先前位置。
但我通常对C中的经验如何考虑有效的状态机/协程感兴趣结构化编程。
谢谢
I believe setjmp allows you to "unwind" the stack to a prior position in
the routine when longjmp is then called.
But I''m generally interested in how the experienced in C consider
efficient state machines/coroutine structured programming.
Thanks
嗨Dieter，
嗯...几乎所有我在C中做的是作为状态机的一部分，但是我没有遇到需要使用setjmp / longjmp，我们需要每一点
的效率我们可以获得（在某些情况下）。
我会有兴趣听到其他人说的话......
你有吗您想要实现的一个简单示例？
Hi Dieter,
Hmm... nearly everything I do in C is as part of state mechines, but I
have not come across a need to use setjmp / longjmp, we need every bit
of efficiency that we can get (in some cases).
I''ll be interested to hear what other poeple have to say...
Do you have a simple example of what you are trying to achieve?
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