从两个字符串之间的字符串数组中获取子字符串和char“ [英] Get substring from string array between two char " and char "

问题描述

我想从字符串数组中分隔一个子字符串，其中我的开头是Char（）和我的结尾字符（）。



我的代码：

I want to separate a sub string from a string array where my start Char (") and my ending Char (").

My Code:

int count = 0;
string[] arr1 = new string[reply.Length-20];
foreach (string item in list)
               {
                   arr1[count] = item.Split(new Char[] { '"','"' });
                   Console.WriteLine(item);
                   count = count + 1;
               }

请帮我将子字符串从字符串whit start char分隔到end char。

提前致谢。



我尝试过：



arr1 [count] = item.Split（new Char [] {''，''}）;

Please help me to separate a substring from a string whit start char to end char.
Thanks in advance.

What I have tried:

arr1[count] = item.Split(new Char[] { '"','"' });

推荐答案

拆分不这样的工作！

可能你想要的是：

Split doesn't work like that!
Possibly what you want is:

int count = 0;
foreach (string item in list)
    {
    string[] arr1 = item.Split(new char[] {'"'}, StringSplitOptions.RemoveEmptyEntries);
    foreach (string s in arr1)
        {
        Console.WriteLine(s);
        count = count + 1;
        }
    }

问题不是很清楚。但是， String.split 返回一个数组，因此你不能将结果存储在 arr1 [count] 中，因为那是一个字符串参考。不是字符串[] 引用。同样为什么要打印 item 在下一行，而不是一些拆分数据？您可能需要执行以下操作：

The issue is not really clear. However, String.split returns an array, so you cannot store the result in arr1[count], since that is a string reference. not a string[] reference. Similarly why are you printing item in the next line, rather that some split data? You probably need to do something like:

foreach (string item in list)
{
    string[] splits = item.Split(new Char[] { '"','"' });
// do something with the split subitems
}

目前还不清楚你想用这个代码做什么，但它可以简化。

It is not clear what you want to do with this code, but it can be simplified.

int count = 0;
string[] arr1 = new string[reply.Length-20];
foreach (string item in list)
    {
       arr1[count] = item.Split(new Char[] { '"','"' });
       Console.WriteLine(item);
       count = count + 1;
    }

您对变量 count

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