将json数组解析为XML [英] Parse json array to XML

问题描述

如何将json数据解析并存储到以下JSON格式中指定的XML文件中



{

结果：[

[id，name]，

[1，Peta]，

[2，Aachara]，< br $> b $ b [3，Aanjangaon]，

[4，Aanjar]，

[5，Aathankarai]，
[6，Abu]，

[7，Abu Road]，

[8，Achanta]，

[9，Addanki]，

[10，Addavaram]，

[11，Adipur]，

[12，Adirampattinam]，

[13，Adoni]

]

}



我尝试过：



HttpWebResponse response =（HttpWebResponse）request.GetResponse（）; < br $>


流resStream = response.GetResponseStream（）;



string tempString = null;



int count = 0;

< br $> b $ b do

{

count = resStream.Read（buf，0，buf.Length）;



if（count！= 0）

{

tempString = Encoding.ASCII.GetString（buf，0，count）;



sb.Append（tempString）;

}

}

while（count> 0）; //还有更多要阅读的数据吗？



字符串数据= sb.ToString（）;



/ ************************************* /

JavaScriptSerializer js = new JavaScriptSerializer（）;



JavaScriptSerializer ser = new JavaScriptSerializer（）;



var obj = ser.DeserializeObject （数据）作为ICollection;



StringBuilder sbxml = new StringBuilder（）;



sbxml.Append（ ）;



StringWriter sw = new StringWriter（）;



XmlTextWriter wr = new XmlTextWriter（ sw）;



wr.WriteStartDocument（）;



foreach（KeyValuePair< string，> item在obj）

{

sbxml.Append（<+ item.Key +>）;



wr.WriteStartElement（item.Key）;



foreach（var i in（item.Value as object []））

{

foreach（var val in（i as ICollection））

{

sbxml.Append（<+ val +>）;



wr .WriteStartElement（val.ToString（））;





sbxml.Append（）;

wr .WriteEndElement（）;

}

}



sbxml.Append（）;

wr.WriteEndElement（）;

}



wr.WriteEndDocument（）;

wr .Flush（）;

wr.Close（）;

How to parse and store json data into XML file as specified in below JSON format

{
"result": [
["id", "name"],
[1, "Peta"],
[2, "Aachara"],
[3, "Aanjangaon"],
[4, "Aanjar"],
[5, "Aathankarai"],
[6, "Abu"],
[7, "Abu Road"],
[8, "Achanta"],
[9, "Addanki"],
[10, "Addavaram"],
[11, "Adipur"],
[12, "Adirampattinam"],
[13, "Adoni"]
]
}

What I have tried:

HttpWebResponse response = (HttpWebResponse)request.GetResponse();

Stream resStream = response.GetResponseStream();

string tempString = null;

int count = 0;

do
{
count = resStream.Read(buf, 0, buf.Length);

if (count != 0)
{
tempString = Encoding.ASCII.GetString(buf, 0, count);

sb.Append(tempString);
}
}
while (count > 0); // any more data to read?

string data = sb.ToString();

/*************************************/
JavaScriptSerializer js = new JavaScriptSerializer();

JavaScriptSerializer ser = new JavaScriptSerializer();

var obj = ser.DeserializeObject(data) as ICollection;

StringBuilder sbxml = new StringBuilder();

sbxml.Append("");

StringWriter sw = new StringWriter();

XmlTextWriter wr = new XmlTextWriter(sw);

wr.WriteStartDocument();

foreach (KeyValuePair<string,> item in obj)
{
sbxml.Append("<" + item.Key + ">");

wr.WriteStartElement(item.Key);

foreach (var i in (item.Value as object[]))
{
foreach (var val in (i as ICollection))
{
sbxml.Append("<" + val + ">");

wr.WriteStartElement(val.ToString());


sbxml.Append(");
wr.WriteEndElement();
}
}

sbxml.Append(");
wr.WriteEndElement();
}

wr.WriteEndDocument();
wr.Flush();
wr.Close();

推荐答案

使用此在JSON和XML之间转换 [ ^ ]

add Newtonsoft.Json .dll 参考 [ ^ ]

use this Converting between JSON and XML[^]
add Newtonsoft.Json.dll reference[^]

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