如何转换ArrayList< Object>使用JAXB的XML？ [英] How to Convert ArrayList<Object> to a XML using JAXB?

问题描述

我正在尝试使用JAXB将ArrayList转换为xml ..

I am trying to convert ArrayList to xml using JAXB..

ArrayList<LDAPUser> myList = new ArrayList<LDAPUser>();

    myList = retrieveUserAttributes.getUserBasicAttributes(lastName,
            retrieveUserAttributes.getLdapContext());



    JAXBContext jaxbContext = JAXBContext.newInstance(LDAPUser.class);
    Marshaller jaxbMarshaller = jaxbContext.createMarshaller();

    StringWriter sw = new StringWriter();

    jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

     jaxbMarshaller.marshal(myList, sw);
     System.out.println(sw.toString());     
     return sw.toString();

...
但它不起作用，我收到此错误：

... but its not working, I am getting this error:

27-Aug-2012 10:43:58 org.apache.catalina.core.StandardWrapperValve
调用SEVERE：Servlet.service（）对于带有
路径[/ Spring3-LDAP-WebService]的上下文中的servlet [spring]抛出异常[请求处理
失败;嵌套异常是javax.xml.bind.JAXBException：类
java.util.ArrayList或它的任何超类都知道这个
上下文。]的根本原因是javax.xml.bind。 JAXBException：类
java.util.ArrayList或它的任何超类都知道这个
上下文。 at
com.sun.xml.internal.bind.v2.runtime .JAXBContextImpl.getBeanInfo（JAXBContextImpl.java:554）
at
com.sun.xml.internal.bind.v2.runtime.XMLSerializer.childAsRoot（XMLSerializer.java:470）
at
com.sun.xml.internal.bind.v2.runtime.MarshallerImpl.write（MarshallerImpl.java:314）
at
com.sun.xml.internal.bind.v2.runtime。 MarshallerImpl.marshal（MarshallerImpl.java:243）
at
javax.xml.bind.helpers.AbstractMarshallerImpl.marshal（AbstractMarshallerImpl.java:96）
at
ie.revenue。 spring.RestController.searchLdapUsersByLastNameTwo（RestController.java:69）
at sun.reflect.NativeMethodAccessorImpl.invoke0（Native Method）a t
sun.reflect.NativeMethodAccessorImpl.invoke（NativeMethodAccessorImpl.java:39）............

27-Aug-2012 10:43:58 org.apache.catalina.core.StandardWrapperValve invoke SEVERE: Servlet.service() for servlet [spring] in context with path [/Spring3-LDAP-WebService] threw exception [Request processing failed; nested exception is javax.xml.bind.JAXBException: class java.util.ArrayList nor any of its super class is known to this context.] with root cause javax.xml.bind.JAXBException: class java.util.ArrayList nor any of its super class is known to this context. at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.getBeanInfo(JAXBContextImpl.java:554) at com.sun.xml.internal.bind.v2.runtime.XMLSerializer.childAsRoot(XMLSerializer.java:470) at com.sun.xml.internal.bind.v2.runtime.MarshallerImpl.write(MarshallerImpl.java:314) at com.sun.xml.internal.bind.v2.runtime.MarshallerImpl.marshal(MarshallerImpl.java:243) at javax.xml.bind.helpers.AbstractMarshallerImpl.marshal(AbstractMarshallerImpl.java:96) at ie.revenue.spring.RestController.searchLdapUsersByLastNameTwo(RestController.java:69) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)...........

请帮忙！
谢谢。

Please help! Thanks.

推荐答案

尝试创建一个包装列表并使其成为xml根的类，例如：

Try to create a class that wraps your list and make it a xml root, e.g.:

@XmlRootElement
class LDAPUsers {
    private List<LDAPUser> users;
    ... get ... set ... constructor 
}

然后编组LDAPUsers对象。

Then marshal LDAPUsers object.

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