删除解析表中的一行 [英] Delete a row from Parse Table
问题描述
我有一个表称为收藏标签。它有田 - 标签,用户(指针 - respectiv用户OBJECTID)。凡用户可以存储标记,并随着用户OBJECTID为指针用户归档和用户钟爱的删除标记 P>
有关存储/更新:它工作正常。
的parseObject favtagobject =新的parseObject(最爱);
favtagobject.put(变量,#+关键字);
favtagobject.put(用户,ParseUser.getCurrentUser());
favtagobject.saveInBackground();
有关删除/从表中删除标签:低于code不能正常工作
的parseObject favtagobject =新的parseObject(最爱);
favtagobject.put(变量,#+关键字);
favtagobject.put(用户,ParseUser.getCurrentUser());
favtagobject.deleteInBackground(新DeleteCallback(){ @覆盖
公共无效完成(com.parse.ParseException为arg0){
// TODO自动生成方法存根
的System.out.println(删除成功标记);
}
});
我想删除表我知道哪一行要被删除的行。请帮助我。
基本上,当您使用新的parseObject(最爱);这将构建一个新的parseObject。直到调用.save()上的任何变体本的parseObject不存在于数据库中。因此,当你做到这一点。
的parseObject favtagobject =新的parseObject(最爱);
favtagobject.put(变量,#+关键字);
favtagobject.put(用户,ParseUser.getCurrentUser());
favtagobject.deleteInBackground(新DeleteCallback(){ @覆盖
公共无效完成(com.parse.ParseException为arg0){
// TODO自动生成方法存根
的System.out.println(删除成功标记);
}
});
所有你正在做的是创造一个新的对象,不存在于数据库中,然后尝试将其删除?什么你要找的就是这个。
ParseQuery<&的parseObject GT;查询= ParseQuery.getQuery(最爱);
query.whereEqualTo(变量,#+关键字);
query.whereEqualTo(用户,ParseUser.getCurrentUser());
query.getFirstInBackground(新FindCallBack(){ @覆盖
公共无效做过(的parseObject对象,com.parse.ParseException为arg0){
// TODO自动生成方法存根
object.delete();
object.saveInBackground();
}
}));
这将首先从数据库中获取对象,然后删除表中的行并保存到对象所做的更改!
I have a table called Favourite tags. it has fields - Tag, User( Pointer- respectiv user objectid).where User can store a tag and along with user-objectid as pointer in user filed and user remove the tag from favourite
For Storing/Updating: it is working fine .
ParseObject favtagobject = new ParseObject("Favourite");
favtagobject.put("Tag", "#" + keyword);
favtagobject.put("User", ParseUser.getCurrentUser());
favtagobject.saveInBackground();
For removing/deleting the tag from table: Below code is not working
ParseObject favtagobject = new ParseObject("Favourite");
favtagobject.put("Tag", "#" + keyword);
favtagobject.put("User", ParseUser.getCurrentUser());
favtagobject.deleteInBackground(new DeleteCallback() {
@Override
public void done(com.parse.ParseException arg0) {
// TODO Auto-generated method stub
System.out.println("deleted the tag succesfully");
}
});
i want to delete a row from table i know which row to be deleted. Please help me out.
Basically, when you use 'new ParseObject("Favourite");' it will construct a new ParseObject. This parseObject does not exist in your database until you call any variant of .save() on it. Hence when you do this
ParseObject favtagobject = new ParseObject("Favourite");
favtagobject.put("Tag", "#" + keyword);
favtagobject.put("User", ParseUser.getCurrentUser());
favtagobject.deleteInBackground(new DeleteCallback() {
@Override
public void done(com.parse.ParseException arg0) {
// TODO Auto-generated method stub
System.out.println("deleted the tag succesfully");
}
});
All you're doing is creating a new object, that does not exist in your database and then try to delete it? What you're looking for is this
ParseQuery<ParseObject> query = ParseQuery.getQuery("Favourite");
query.whereEqualTo("Tag", "#" + keyword);
query.whereEqualTo("User", ParseUser.getCurrentUser());
query.getFirstInBackground(new FindCallBack() {
@Override
public void done(ParseObject object, com.parse.ParseException arg0) {
// TODO Auto-generated method stub
object.delete();
object.saveInBackground();
}
}););
This will first get the object from your database and then delete the row from table and save the changes made to the object!
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