格式化十进制变量 [英] To format the decimal variable

问题描述

我该如何格式化十进制变量?
假设
我声明了十进制类型变量i = 0;
我是6.1056.
其实我想得到的值是6.11
我将如何解决以上问题???
请帮助我....

How can i format the decimal variable??
Suppose,
I declare decimal type variable i = 0;
and i is 6.1056.
Actually I want to get the value is 6.11
how will i do above problem????
Please help me....

推荐答案

看看 ^ ]

Have a look at Math.Round [^]

decimal a = 1.994444M;
Math.Round(a, 2); //returns 1.99

来自 http://stackoverflow.com /questions/257005/how-do-you-round-a-number-to-two-decimal-places-in-c [ ^ ]

from http://stackoverflow.com/questions/257005/how-do-you-round-a-number-to-two-decimal-places-in-c[^]

尝试一下

Try this

i = Math.Round(6.1056,2);

如解决方案1和2所述，此处解释了Math 类的Round方法
Math.Round方法(十进制，Int32，MidpointRounding) [

As already given in Solution 1 and 2, the Round method of Math class explained here
Math.Round Method (Decimal, Int32, MidpointRounding)[^]
can be used as follows:

decimal number = 6.1056M;
Console.WriteLine (Math.Round(number,2));

默认情况下，Round 方法使用此处解释的MidpointRounding.ToEven枚举值 http://msdn.microsoft .com/en-us/library/system.midpointrounding.aspx [

By default the Round method uses MidpointRounding.ToEven enumeration value explained here http://msdn.microsoft.com/en-us/library/system.midpointrounding.aspx[^], which means that if the value to be rounded is 6.105 it will be rounded off to 6.10 and if it is 6.115 then it will be rounded off to 6.12 as 5 is the mid point.

If the MidpointRounding.AwayFromZero is used as shown below

decimal number = 6.1056M;
Console.WriteLine (Math.Round(number,2, MidpointRounding.AwayFromZero));

那么上述值将分别四舍五入为6.11和6.12，即始终为数字away from zero，即将采用next higher number.

then the above values will be rounded off to 6.11 and 6.12 respectively, i.e. always the number away from zero, in other words the next higher number will be taken.

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