我想在两个变量之间执行按位与(&)操作，但是我在double中有一个值.但是double不允许按位运算. [英] I want to perform a bitwise and(&) operation between two variable.but I have one value in double.but double does not allow bitwise opearation.

问题描述

我想在两个数字之间执行按位运算.一个是double类型，另一个是int类型.当我执行代码时，得到的例外是.double和int之间无法执行按位和运算.

我尝试过的事情:

字符串add64 ="0013A2004154EC8E";
double num_add64 = Int64.Parse(add64，System.Globalization.NumberStyles.HexNumber);
int sumadd =(int)sum;
整数r = sumadd& ck;

类型转换后.在sumadd变量中，我得到负值.这就是问题所在.
请帮助我.谢谢您.

I want to perform a bit wise operation between two number.one is of double type and other is of int type.And when i am executing the code getting the exception that.Bitwise and operation can not be performed between double and int.

What I have tried:

string add64 = "0013A2004154EC8E";
double num_add64 =Int64.Parse(add64, System.Globalization.NumberStyles.HexNumber);
int sumadd = (int)sum;
int r = sumadd & ck;

after type casting .In sumadd variable i m getting negative value.That is the problem.
Please help me.Thank you in advance.

推荐答案

为什么要将Int64分配给double?

将第二个操作数ck强制转换为Int64并执行以下操作:

Why are you assigning the Int64 to a double?

Cast the second operand ck to Int64 instead and perform the operation:

Int64 num_add64 =Int64.Parse(add64, System.Globalization.NumberStyles.HexNumber);
int r = Convert.ToInt32(num_add64 & Convert.ToInt64(ck));

因为您要处理不同宽度的整数并执行AND操作，所以应检查在这里使用uint是否可能是更好的选择(假设ck是uint):

Because you are dealing with integers of different width and performing an AND operation, you should check if using uint might be a better choice here (assuming ck is an uint):

UInt64 num_add64 =UInt64.Parse(add64, System.Globalization.NumberStyles.HexNumber);
uint r = Convert.ToUInt32(num_add64) & ck;

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