在Python中的嵌套IF中调用函数 [英] Calling function in nested IF in Python

问题描述

我必须接受用户输入的鸟名并检查bird_names列表.

我尝试了以下代码:
第一个输入:蝴蝶
输出:

I have to take the user inputs of bird names and check in the list of bird_names.

I have tried the following code:
first input: butterfly
output:

2nd try fail, please do 3rd try

在第二次尝试
输入:鹦鹉
输出:<

On 2nd try
input: parrot
output: <

1st try fail, do 2nd try

''

斜体代码不起作用.

请告诉我我的逻辑哪里错了.

提前谢谢！

我尝试过的事情:

''

The code in italics is not working.

Kindly tell me where I am wrong in my logic.

Thanks in advance!

What I have tried:

bird_names=(''crow'', ''parrot'', ''eagle'')
def bird_guess():
    bird_guess1=input(''Enter the bird guess :'')
    return bird_guess1

bird_guess()

if(bird_guess not in bird_names):
        print(''1st try fail, do 2nd try'')
         bird_guess()
        if(bird_guess not in bird_names):
            print(''2nd try fail, please do 3rd try'')
            bird_guess()
            if(bird_guess not in bird_names):
                print(''Sorry, exhausted tries'')
            else:
                print(''corect on 3rd try'')
        elif(bird_guess  in bird_names):
                    print(''good work! correct on 2nd try'')
elif(bird_guess  in bird_names): 
                        print(''great work!, correct on 1st try itself'')
    
else:
    print(''Not Valid'')

推荐答案

您在测试中使用的是bird_guess 函数，而不是其返回值.试试

You are using bird_guess function, instead of its return value in your tests. Try

bird_names=('crow', 'parrot', 'eagle')
def bird_guess():
    bird_guess1=input('Enter the bird guess :')
    return bird_guess1

guess = bird_guess()

if(guess not in bird_names):
    print('1st try fail, do 2nd try')
    guess = bird_guess()
    if(guess not in bird_names):
        print('2nd try fail, please do 3rd try')
        guess = bird_guess()
        if(guess not in bird_names):
            print('Sorry, exhausted tries')
        else:
           print('corect on 3rd try')
    else:
       print('good work! correct on 2nd try')
else:
    print('great work!, correct on 1st try itself')

尝试一下:

Try this:

bird_names=('crow', 'parrot', 'eagle')
def bird_guess():
    bird_guess1=input('Enter the bird guess :')
    return bird_guess1

def birdtest():

    for count in range(1,4):
        bird = bird_guess()
        if(bird not in bird_names):
            print('try', count, 'failed, ', end='')
            if count < 3:
                print('try again')
            else:
                print('no more guesses allowed.')
                break
        else:
            print("correct, it is in the list")
            break

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