如何并排合并两个表的结果? [英] How to join the results of 2 tables side-by-side?

问题描述

我有2个查询，它们再现了2个结果，

I have 2 queries reproducing 2 results as:

结果1:

select title1,age1 from tab1 where title1 in ('1','2')

title1 age1 
1       2
2       3

结果2:

select title2,age2 from tab2 where title2 in ('a','c')

title2 age2
a       b
c       d

我希望我的结果简单地并排在一起作为最终结果:

I want my results simply joined together side-by-side as a final result:

title1 age1 title2 age2
1       2     a        b
2       3     c        d

如何轻松实现这一目标?我搜索了但没有找到解决方案.

How do I achieve this in an easy way? I searched but didn't find the solution.

==更新表的模式

+--------+---------+------+-----+---------+-------+
| Field  | Type    | Null | Key | Default | Extra |
+--------+---------+------+-----+---------+-------+
| title1 | int(11) | YES  |     | NULL    |       |
| age1   | int(11) | YES  |     | NULL    |       |
+--------+---------+------+-----+---------+-------+
2 rows in set (0.01 sec)

mysql> describe tab2;
+--------+------------+------+-----+---------+-------+
| Field  | Type       | Null | Key | Default | Extra |
+--------+------------+------+-----+---------+-------+
| title2 | varchar(2) | YES  |     | NULL    |       |
| age2   | varchar(2) | YES  |     | NULL    |       |
+--------+------------+------+-----+---------+-------+

===更新: 我尝试了以下操作:

=== update: I tried following:

select * from 
(select title1, age1 from tab1 order by title1,age1) as result1 , 
(select title2, age2 from tab2 order by title2,age2) as result2 ; 

它产生了4行:

+--------+------+--------+------+
| title1 | age1 | title2 | age2 |
+--------+------+--------+------+
|      1 |    2 | a      | b    |
|      2 |    3 | a      | b    |
|      1 |    2 | c      | d    |
|      2 |    3 | c      | d    |
+--------+------+--------+------+

推荐答案

我认为这对您有用.

-示例

select result1.title1, title1.age1,result2.title2, title2.age2 from 
  (select @i:=@i+1 AS rowId, title1, age1 from tab1,(SELECT @i:=0) a) as result1 , 
  (select @j:=@j+1 AS rowId,title2, age2 from tab2,(SELECT @j:=0) a ) as result2 
where 
  result1.rowId = result2.rowId; 
-- try this it will work perfectly fine

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