替换或删除第n个\ n [英] Replace or remove nth occurrence of \n

问题描述

这是我的字符串:

var ok = "\n\n33333333333\n\n\n";

如何用''替换'\ n'的第四次出现? 或者，如何删除"\ n"的第四次出现?

How to replace the 4th occurence of '\n' with ''? Or, how to remove the 4th occurence of '\n'?

推荐答案

• 找到n-1次出现和其他字符.
• 捕获子匹配项.
• 找到下一个事件.

• 将整个匹配项替换为捕获的子匹配项，然后 替换字符/字符串

  • find n-1 occurences and other characters.
  • capture the submatch.
  • find the next occurence.

  • replace the entire match with the captured submatch, and the replacement character/string

    "AA33333333333AAA".replace(/((?:[^A]*A){3}[^A]*)A/,"$1k")

    (具有\n和""的A和k安装，因此您可以更清楚地看到结果)

    (with A and k insteead of \n and "" so you can more clearly see the results)

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