无法反序列化当前JSON对象(例如{"name":"value"}) [英] Cannot deserialize the current JSON object (e.g. {"name":"value"})

问题描述

这是我的JSON数据

{
    "logInResult": [
        {
            "Name": "yogesh singh",
            "cityName": "",
            "img": "DefaultImage/D_Vp_Men.png",
            "usrId": "374"
        }
    ]
}

这是我的代码

public async Task<ActionResult> Index()
{

    HttpClient webClient1 = new HttpClient();
    Uri uri = new Uri("http://m.vinipost.com/service/userprofile.svc/logIn?loginId=[e-mail]&pass=12345");

    HttpResponseMessage response1;

    response1 = await webClient1.GetAsync(uri);

    var jsonString = await response1.Content.ReadAsStringAsync();

    var _Data = JsonConvert.DeserializeObject<List<JClass>>(jsonString);
    foreach (JClass Student in _Data)
    {
        ViewBag.Message += Student.Name + ", ";
    }
    dynamic obj = JsonConvert.DeserializeObject(jsonString);
    ViewBag.Message += obj.data.Name;

    return View();
}

错误是

无法将当前JSON对象(例如{"name":"value"})反序列化为类型'System.Collections.Generic.List`1 [MvcSumit1.Models.JClass]'，因为该类型需要JSON数组(例如[1,2,3])正确反序列化. 要解决此错误，可以将JSON更改为JSON数组(例如[1,2,3])，也可以更改反序列化类型，使其成为普通的.NET类型(例如，不像整数这样的原始类型，也不像这样的集合类型.数组或列表)，可以从JSON对象反序列化.还可以将JsonObjectAttribute添加到类型中，以强制其从JSON对象反序列化. 路径"logInResult"，第1行，位置15.

Cannot deserialize the current JSON object (e.g. {"name":"value"}) into type 'System.Collections.Generic.List`1[MvcSumit1.Models.JClass]' because the type requires a JSON array (e.g. [1,2,3]) to deserialize correctly. To fix this error either change the JSON to a JSON array (e.g. [1,2,3]) or change the deserialized type so that it is a normal .NET type (e.g. not a primitive type like integer, not a collection type like an array or List) that can be deserialized from a JSON object. JsonObjectAttribute can also be added to the type to force it to deserialize from a JSON object. Path 'logInResult', line 1, position 15.

推荐答案

您不能使用JsonConvert.DeserializeObject.

请尝试以下代码:

JObject jsonResponse = JObject.Parse(jsonString);
JObject objResponse = (JObject)jsonResponse["logInResult"];
Dictionary<string, JArray> _Data = Newtonsoft.Json.JsonConvert.DeserializeObject<Dictionary<string, JArray>>(objResponse.ToString());

希望这会对您有所帮助.

Hope this will help you.

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