从MySQL数据库中检索BLOB图像和Android的ListView中显示 [英] Retrieving blob images from mysql database and displaying in android listview

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本文介绍了从MySQL数据库中检索BLOB图像和Android的ListView中显示的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我已经包含有关的文章和图片(存储为BLOB)信息命名文章的phpmyadmin创建了一个数据库。我为能够从数据库获取数据,并在android列表视图中显示,但即​​时通讯没有得到如何从数据库中检索一个blob的图像,并与Android的列表视图中的相应文章信息一起显示出来..请帮助我..我没有使用Google的很多,但我没有做到..
任何链接教程或贴会很greatfull任何code ...我需要这为我的项目..
在此先感谢:)

I have created a database in phpmyadmin named article that contains information regarding the articles and an image(stored as blob). I m able to fetch the data from the data base and display it in the android list view but i m not getting how to retrieve a blob image from the database and display it along with the corresponding article information in android list view.. please help me.. i did lot of googling but i failed to do.. Any link to tutorial or any code posted will be very greatfull... i need this for my project.. Thanks in advance :)

我的PHP code是 -

My php code is -

<?php
header('Content-type: application/json');
mysql_query('SET CHARACTER SET utf8');
mysql_connect("localhost","root","");
mysql_select_db("reader");
$id=$_REQUEST['keyword'];
$id1=(int)$id;
$sql=mysql_query("SELECT * FROM article a WHERE a.a_id='{$id}'");
while($row=mysql_fetch_assoc($sql))
{
$row['a_thumbnail']=base64_encode($row['a_thumbnail']);
$row1= array_slice($row, 0, 2);
$row_slice=array_slice($row,2);
$output2=array_map('utf8_encode', $row_slice);
$output[]=array_merge((array)$row1, (array)$output2);
}
print(json_encode($output));
mysql_close();
?>

化java code我写来获取图像 -

The java code i wrote to retrieve image is-

public class SearchByLikeCount extends ListActivity {
ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();

@Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main2);
        String result = "";
        InputStream is= null;
        try{
                HttpClient httpclient = new DefaultHttpClient();
                HttpGet httpget = new HttpGet("http://10.0.2.2/likeCountsearch.php");
                HttpResponse response = httpclient.execute(httpget);
                HttpEntity entity = response.getEntity();
                is = entity.getContent();
        }catch(Exception e){
                Log.e("log_tag", "Error in http connection "+e.toString());
        }
        try{
                BufferedReader reader = new BufferedReader(new InputStreamReader(is,"utf-8"),8);
                StringBuilder sb = new StringBuilder();
                String line = null;
                while ((line = reader.readLine()) != null) {
                        sb.append(line + "\n");
                }
                is.close();

                result=sb.toString();
        }catch(Exception e){
                Log.e("log_tag", "Error converting result "+e.toString());
        }
        try{
                JSONArray jArray = new JSONArray(result);
                for(int i=0;i<jArray.length();i++){

                    HashMap<String,String> map = new HashMap<String, String>();
                    JSONObject e = jArray.getJSONObject(i);
                    Log.i("shruthi", "jason object length = " + e.length());
                    map.put("id",  e.getString("a_id"));
                    map.put("title",  e.getString("a_title"));
                    map.put("author",  e.getString("a_author"));
                    map.put("image", e.getString("a_thumbnail"));
                    mylist.add(map);
            }
               }catch(JSONException e)        {
                 Log.e("log_tag", "Error parsing data "+e.toString());
               }

        ListAdapter adapter = new SimpleAdapter(SearchByLikeCount.this, mylist , R.layout.main2,
        new String[] { "title", "author","image"},
        new int[] { R.id.item_title ,R.id.item_author,R.id.list_image});

        setListAdapter(adapter);

        final ListView lv = getListView();
        lv.setTextFilterEnabled(true);
        lv.setOnItemClickListener(new OnItemClickListener() {
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
        @SuppressWarnings("unchecked")
        HashMap<String, String> o = (HashMap<String, String>) lv.getItemAtPosition(position);
        Object v=o.get("id");
        String id1=v.toString();
        Intent myintent= new Intent(SearchByLikeCount.this,ViewArticle.class);
        myintent.putExtra("articleId", id1);
        startActivity(myintent);
        }
    }); 
 }
}

这没有工作:(可以在任何分不清什么是错误,我做了??

This didnt work :( can any tell what was the mistake i did??

推荐答案

也许你可以存储在文件夹中的形象
结果
并存储在数据库中的文件夹链接,并通过您的链接检索图像
结果

Maybe you can store the image in folders
and store the folder link in your database, and retrieve the image by your link

   try 
{
    Bitmap bitmap = BitmapFactory.decodeStream((InputStream)new URL(imageUrl).getContent());
    imageView.setImageBitmap(bitmap); 
} 
catch (MalformedURLException e) 
{
      e.printStackTrace();
} 
catch (IOException e)
 {
       e.printStackTrace();
 }

这篇关于从MySQL数据库中检索BLOB图像和Android的ListView中显示的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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