以json格式获取表数据 [英] Get Table data in json format
本文介绍了以json格式获取表数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
大家好,我要获取json格式的表数据的地方是我的表
Hello everyone I'm trying to get table data in json format here is my table
<table>
<thead>
<tr>
<th>srno</th>
<th>name</th>
<th>email</th>
</tr>
</thead>
<tbody>
<tr>
<td>1</td>
<td>Jhon One</td>
<td>Doe one</td>
</tr>
<tr>
<td>2</td>
<td>Jhon two</td>
<td>Doe Two</td>
</tr>
</tbody>
</table>
<button>
convert
</button>
我得到的结果是这个
{
"0": {
"1",
"Jhon One",
"Doe one"
}
,
"1": {
"2",
"Jhon two",
"Doe Two"
}
}
使用以下javascript
using the below javascript
$("button").click(function() {
var json = html2json();
alert(json);
});
function html2json() {
var json = '{';
var otArr = [];
// var i = 1;
var tbl2 = $('table tbody tr').each(function(e) {
x = $(this).children();
var itArr = [];
x.each(function() {
itArr.push('"' + $(this).text() + '"');
});
otArr.push('"' + e + '": {' + itArr.join(',') + '}');
})
json += otArr.join(",") + '}'
return json;
}
但是我想将键添加到每个值,并且数字应从1开始而不是从0开始.
but i want to add key to every value and the number should start from one and not zero.
我有一组欲望结果,它应该看起来像这样 感谢您的帮助
i have a set of desire result and it should look like this any help is appreciated
{
"1": {
no: "1",
name:"Jhon One",
lastname "Doe one"
}
,
"2": {
no: "1",
name:"Jhon two",
lastname "Doe two"
}
}
这是我尝试过的fiddel链接
here is the fiddel link which i have tried
https://jsfiddle.net/k228n2bn/
推荐答案
只需更改以下行
otArr.push('"' + e + '": {' + itArr.join(',') + '}');
到
otArr.push('"' + (e+1) + '": {' + itArr.join(',') + '}');
括号将把值添加为数字而不是字符串.
The parenthesis will add the values as numbers not strings.
此外,为内部对象键添加keys
数组.
Also, add keys
array for internal object keys.
function html2json() {
var json = '{';
var otArr = [];
// var i = 1;
var tbl2 = $('table tbody tr').each(function(e) {
x = $(this).children();
var itArr = [];
var keys = ['no','name','lastname'];
x.each(function(i) {
itArr.push('"' + keys[i] + '":"' + $(this).text() + '"');
});
otArr.push('"' + (e+1) + '": {' + itArr.join(',') + '}');
})
json += otArr.join(",") + '}'
return json;
}
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