laravel 5路由传递两个参数 [英] laravel 5 route passing two parameters
本文介绍了laravel 5路由传递两个参数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有这条路线
Route::get('/artist/{id}/{name}', 'HomeController@artist')->where(['id' => '[0-9]+', 'name' => '[a-z]+'])->name('artist');
这是我的链接
<a href="{{route('artist',$artist->id,$artist->name)}}">{{$artist->name}}</a>
这是HomeController上的artist方法
and this is the artist method on HomeController
public function artist($id, $name){ $artist = Artist::where('id', $id)->where('name', $name)->first();
return view('front.artist', compact('artist'));
}
我不知道此显示错误.这是错误.所以请任何人帮我我在学习幼虫中间.
i donot know this display error. this is the error. so please any one help me with this. iam in the middle of learning laravel.
ErrorException in UrlGenerationException.php line 17:
Missing required parameters for [Route: artist] [URI: artist/{id}/{name}]. (View: C:\xampp\htdocs\laravel\resources\views\front\home.blade.php)
推荐答案
您必须将参数作为数组传递,请参见 https://laravel.com/docs/5.4/helpers#method-route
Yo must pass the parameters as array, see https://laravel.com/docs/5.4/helpers#method-route
route('artist',['id' => $artist->id, 'name' => $artist->name])
或者您可以使用
{!! link_to_route('artist', $artist->name, ['id' => $artist->id, 'name' => $artist->name]) !!}
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