有什么办法可以同时运行2个循环? [英] any way to run 2 loops at the same time?

问题描述

我想为银行队列创建一个c ++程序.每3分钟就有一个新客户进入该队列.每个客户需要5分钟的服务时间.程序在前30分钟后打印出信息

I want to create a c++ program for a bank queue. Where every 3 minutes a new customer enters the queue. every customer needs 5 minutes for the service. The program print out the information after the first 30 minutes

• 每个客户的到达时间
• 每个客户的离开时间
• 排队有多少客户?
• 当前服务的客户是谁?

我编写了当前代码:

#include <queue>
#include <ctime>
#include <time.h>
#include <conio.h>
#include <windows.h>
#include <iostream>
using namespace std;

int main()
{
queue <int> inq;
queue <int> inservice;
int z= 1;

for(int i=0; i<=9; i++)
{
    inq.push(z);
    Sleep(180000);
    _strtime_s(hold_time);
    cout<<"Time of arriving for customer number "<<z<<" is: "<<hold_time<<endl;
    z++;
}

do
{
    inservice.push(inq.front());
    Sleep(300000);
    _strtime_s(hold_time);
    cout<<"Time of leaving for customer number "<<z<<" is: "<<hold_time<<endl;
    inq.pop();
}
while(!inq.empty());

cout<<"number of customers waiting : "<<inq.size()<<endl;
cout<<"Customer number "<<inservice.front()<< " is currently serving"<<endl;

return 0;

}

当前代码逐行执行；在队列循环完成之前，不会将客户转移到服务中. 要调整时间，我必须同时运行两个循环.这样客户就可以在为其他顾客提供服务的同时进入队列

The current code executes line by line; customers will not be moved to service until the queue loop is done. To adjust time, I have to run the two loops at the same time. such that customers enter the queue at the same time other costumers are being served

有什么建议吗?

推荐答案

一种解决此问题的复杂方法的确会使用线程，但是如果您不想这样做，则应该随着时间的流逝而循环，即

A sophisticated way to approach this would indeed use threading, but if you don't want to do that you should instead loop over time, i.e.

for (int minutes = 1; mintues <= 30; minutes++) {
    // if minutes modulo 3 do something
    // if minutes modulo 5 do something
}

您可以循环播放几秒钟，几微秒之类的时间.

You could loop over seconds, microseconds, whatnot.

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