为什么改名不会破坏我的程序? [英] why name mangling isn't breaking my program?

问题描述

可能重复:
main()在C ++中是否已重载?

Possible Duplicate:
Is main() overloaded in C++?

这是我的代码:

#include <iostream>

int main(void* a, void* b)
{
    std::cout << "hello standalone " << std::endl;                      
    return 0;
}

名称修饰之后，不同的参数名称应具有不同的符号名称(void* a, void* b)与(int, char**应该不同)，但是此程序在运行时没有任何问题.

different parameters should have a different symbol name after name mangling(void* a, void* b) should be different from (int, char**), but this program doesn't have any problem when running.

那是为什么?

推荐答案

因为main是特例，编译器会为此生成特殊代码.通常，main将从启动例程中调用-在较早的编译器中通常称为crt0-用C编写，因此编译器将生成main，就好像它被声明为extern "C"一样.但这绝不是必需的.这只是一个典型的实现.

Because main is a special case, and the compiler generates special code for it. Typically, main will be called from a startup routine—often called crt0 in older compilers—written in C, so the compiler will generate main as if it were declared extern "C". But that's in no way required; it's a just a typical implementation.

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