子目录和Makefile [英] Subdirectories and Makefiles

问题描述

我认为这是一个已被问过很多次的问题，但我找不到正确的方法.

I think this is a question that has been asked many times but I cannot find the right way to do it.

我具有以下结构:

project/
project/Makefile
project/code
project/code/*.cc
project/code/Makefile

当我进入目录"project/code"并调用"make project_code"时，我的代码正在正确编译.

When I am in the directory 'project/code' and call "make project_code" my code is compiling correctly.

我想在项目/"中执行此操作，就像在项目/代码"中一样只是调用"make project_code".

I would like to do that when I am in 'project/', just calling "make project_code" as if I was in 'project/code'.

makefile项目/Makefile"将包含其他规则(例如安装")和一些规则，就像我在项目/代码"中一样.为此，我正在请求您的帮助...谢谢.

The makefile 'project/Makefile' will contain other rules (such as 'install') and some rules to compile as if I was in 'project/code'. And for that, I am requesting your help... Thanks.

推荐答案

最简单的方法是:

CODE_DIR = code

.PHONY: project_code

project_code:
       $(MAKE) -C $(CODE_DIR)

.PHONY规则表示project_code不是需要构建的文件，并且-C标志指示目录更改(等同于在调用make之前运行cd code).您可以使用相同的方法来调用code Makefile中的其他目标.

The .PHONY rule means that project_code is not a file that needs to be built, and the -C flag indicates a change in directory (equivalent to running cd code before calling make). You can use the same approach for calling other targets in the code Makefile.

例如:

clean:
       $(MAKE) -C $(CODE_DIR) clean

这篇关于子目录和Makefile的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！