如何生成3位数字的列表? [英] how to generate a list of 3-digit numbers?

问题描述

如何生成一个三位数的列表，其数字总和等于17?

How can I generate a list of 3-digit numbers for which the sum of their digits equal 17?

例如，假设数字为XYZ，我们将得到X+Y+Z=17

For example assuming number XYZ, we would have X+Y+Z=17

这是我走了多远:

numbers = list(range(1, 1000))

推荐答案

您似乎希望数字的总和为17，而不是数字的总和. >作为但我希望第一个数字+第二个数字+第三个数字= 17?" 表示.

It appears that you want the sum of the digits to be 17 and not the sum of the numbers as the "but I want the first number + the second number + the third number = 17 ?" implies.

所以，看看这个:

result = [x for x in range(100, 1000) if sum(int(y) for y in str(x))==17]
print(result)  # [179, 188, 197, 269, ..., 962, 971, 980]

这篇关于如何生成3位数字的列表?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！