如何在Matlab中将矩阵向量传递给函数参数 [英] How can I pass a matrix vector into a function argument in matlab

问题描述

我有一个10 x 3的矩阵，并希望将10行中的每行用作该函数的参数，该函数希望使用从1到10的迭代获得3个参数. 问题是我无法将每个行向量直接传递给需要3个参数的函数.如何将矩阵行转换为函数可接受的格式?

I have a 10 x 3 Matrix and would like to use each of the 10 rows as arguments to a function expecting 3 arguments using an iteration from 1 to 10. Problem is that I cannot pass each row vector directly into the function expecting 3 arguments. How can I convert the matrix rows to a format acceptable by my function?

这是函数:

XXX = obj(Kc, T1, T2);

呼叫代码:

for i = 1:100                               
    pop(i,1) = 50 - rand*(50-1);
    pop(i,2) = 1 - rand*(1-0.1);
    pop(i,3) = 0.2 - rand*(0.2-0.01); 
    Kc(i) = pop(i,1); 
    T1(i) = pop(i,2); 
    T2(i) = pop(i,3); 

end

for j = 1:10
    kk = randperm(100);
    Tour1 = pop(kk(1:10),:);
    ZET(j) = obj(Tour1(j,:));

end

Tour1是10 x 3矩阵，其行需要变为Kc，T1，T2. 谢谢.

Tour1 is the 10 x 3 matrix whose rows need to become Kc, T1, T2. Thanks.

推荐答案

转换为单元格数组:

for j = 1:10
    kk = randperm(100);
    Tour1 = pop(kk(1:10),:);
    temp = mat2cell(Tour1(j,:),1,ones(1,numel(Tour1(j,:))))
    ZET(j) = obj(temp{:});
end

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