Maven:基于配置文件选择父项目 [英] Maven: Selecting Parent Project Based On Profile

问题描述

我有一个Maven项目-它是jenkins的插件.它的父母应该是:

I have a maven project - it is a plugin for jenkins. It's parent should be a:

<parent>
  <groupId>org.jenkins-ci.plugins</groupId>
  <artifactId>plugin</artifactId>
  <version>1.414</version>
</parent>

但是与此同时，此插件也可以用于hudson，而无需更改任何代码行.但是它的父项目应该是:

But at the same time this plugin can be also used for hudson, without changing any line of code. But the parent project for it should be:

<parent>
  <groupId>org.jvnet.hudson.plugins</groupId>
  <artifactId>hudson-plugin-parent</artifactId>
  <version>2.0.1</version>
</parent>

我可以为此指定两个不同的配置文件，并使用它们分别为jenkins或hudson构建插件吗?这样我就这样称呼:

Can I specify 2 different profiles for that and use them to build plugin for jenkins or hudson accordingly? So that I call something like that:

mvn package -P jenkins

或

mvn package -P hudson

我尝试在配置文件中指定属性，但是这些属性不会被<parent>标记内的值替换.那么，是否还有其他为这两者构建插件的可能性，但是要使用尽可能多的通用代码和文件?

I have tried to specify properties in profiles, but those are not replaced by their values inside the <parent> tag. So is there any other possibility to build plugin for both, but with as much as possible common code and files?

已添加:那么，如果我做不到，那我该怎么办?如何重构?新的结构应该是什么?

Added: So, if I cannot do that, what should I do then? How to refactor? What the new structure should be?

推荐答案

当前，我们决定坚持使用1个存储库和2个单独的pom.xml文件，并提供pom.xml用于构建项目的maven密钥.

Currently we decided to stick with 1 repository and 2 separate pom.xml files, giving maven key which pom.xml use to build the project.

mvn package -f pom-jenkins.xml
mvn package -f pom-hudson.xml

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