直接从源代码创建Web服务客户端 [英] Creating a web-service client directly from the source

问题描述

我正在尝试直接从@Webservice类生成WS客户端jar.

I am trying to generate the WS client jar directly from the @Webservice class(es).

让我们举个例子:

   package com.example.maven.jaxws.helloservice;
   import javax.jws.WebService;
   @WebService
   public class Hello {
     public String sayHello(String param) {
     ;  return "Hello " + param;
     }
   }  

我可以生成一个战争文件并使用glassfish来提供此Web服务，然后从那里我可以使用glassfish WSDL URL来生成客户端源.

I can generate a war file and use glassfish to serve this webservice, and from there I can use the glassfish WSDL URL to generate the client sources.

我想做的是跳过玻璃鱼部分. 从我定义Web服务的Maven项目中，我想使用jaxws-maven-plugin创建客户端类，但是找不到任何方法来指定Web服务的实际URL.

What I am trying to do is to skip the glassfish part. From my maven project defining the webservice, I would like to use the jaxws-maven-plugin to create the client classes but I cannot find any way to specify the actual URL of the webservice.

应该可以吧?

@另请参见创建网络具有已知但无法访问的wsdl的服务客户端

推荐答案

您应使用<wsdlLocation>选项提供在部署后WSDL文件将可用的服务的位置.

You should use <wsdlLocation> option to give the location of the service where the WSDL file is going to be available after deployment.

使用-wsdlLocation开关

还有另一种简单的方法- 只需使用-wsdlLocation运行wsimport 切换并提供WSDL位置 相对于 生成的服务类，您需要 将此WSDL文件放在此相对位置 位置.

There is another easy way to do it - just run wsimport with -wsdlLocation switch and provide the WSDL location value which is relative to the generated Service class and you need to put this WSDL file at this relative location.

有关详细信息，请参见该帖子.

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