在打字稿中获取类的键 [英] Getting keys of a class in typescript

问题描述

我有一个带有很多方法的类，我们称之为myClass.我这样称呼它:

I have a class with a lot of methods let's call it myClass. I'm calling it like this:

myClass[key]()

是否有办法从键中获取可能的值?我希望像myClass的keyof这样的东西，但是我得到了"myClass指向一个值，但是在这里被用作类型"

Is there a way to get the possible values from key? I hoped for something like keyof myClass, but I got 'myClass refers to a value, but is being used as a type here'

问题可能是，到目前为止，myClass已在.js文件中定义并像这样封装:

The problem is probably that as of now myClass is defined in a .js-file and encapsulated like this:

const myClass = new MyActualClass();
export default myClass

是否可以在不将.js文件转换为打字稿的情况下提取信息，并直接从MyActualClass提取信息?

Is it possible to extract the information without converting the .js file to typescript, and extract the information from MyActualClass directly?

推荐答案

要获取运行时属性名称，可以使用Object.keys或Object.getOwnPropertyNames.

在TypeScript级别，如果您想声明一个可能包含类实例的键的变量，您将像这样进行操作:

At the TypeScript level, if you wanted to declare a variable that could contain the keys for an instance of your class, you'd do it like this:

let s: keyof typeof myClass;

实施例在游乐场

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