在opencv中使用Color_YUV2BGR从YUV到BGR的错误转换 [英] Wrong conversion from YUV to BGR using Color_YUV2BGR in opencv

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问题描述

我想将一组YUV值转换为BGR.我的代码如下:

I want to convert a single set of YUV value to BGR. My code is as follows:

yuv = [100, 50, 150]
cv::Mat bgr_mat;
cv::Mat yuv_mat(1,1,CV_8UC3,cv::Scalar(yuv[0],yuv[1],yuv[2]));
cv::cvtColor(yuv_mat,bgr_mat,cv::COLOR_YUV2BGR);
cv::Vec3b bgr = bgr_mat.at<cv::Vec3b>(0,0);
cout << "b: " << (float)bgr.val[0] << " , g: " << (float)bgr.val[1] << " , r: " << (float)bgr.val[2] << endl;

我得到的输出是-b:125,g:118,r:0

The output I get is - b: 125, g: 118, r: 0

但是预期的输出是b:0,g:112,r:128

But the expected output is b: 0, g: 112, r: 128

有人可以告诉我我要去哪里错吗?

Can somebody please tell me where am I going wrong?

推荐答案

如果您使用的是Opencv 2.4,则它是已知的

If you are using Opencv 2.4 It is a known issue

根据对类似问题的答复 有一种可能的工作方式:

Acording to responses on a similar question There is a possible workarond:

yuv = [100, 50, 150]
cv::Mat bgr_mat;
cv::Mat yuv_mat(1,1,CV_8UC3,cv::Scalar(yuv[0],yuv[1],yuv[2]));
cv::cvtColor(yuv_mat,bgr_mat,cv::COLOR_YUV2BGR);
cv::cvtColor(bgr_mat,bgr_mat,cv::COLOR_BGR2RGB);
cv::Vec3b bgr = bgr_mat.at<cv::Vec3b>(0,0);
cout << "b: " << (float)bgr.val[0] << " , g: " << (float)bgr.val[1] << " , r: " << (float)bgr.val[2] << endl;

输出:

b:0,g:118,r:125

b: 0 , g: 118 , r: 125

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