Oracle正则表达式(REGEXP_LIKE)太长错误-ORA-12733 [英] Oracle Regular Expression (REGEXP_LIKE) Too Long Error - ORA-12733

问题描述

我必须在PL/SQL中验证IPv6地址.我从这里想到了正则表达式:正则表达式(RegEx) IPv6与IPv4分开

I have to validate an IPv6 address in PL/SQL. I came up with the regular expression from here: Regular Expression (RegEx) for IPv6 Separate from IPv4

我收到一个ORA-12733: regular expression too long错误.有什么办法解决吗?

I am getting an ORA-12733: regular expression too long error. Is there any way around this?

if ( REGEXP_LIKE(v,'^(([0-9a-fA-F]{1,4}:){7,7}[0-9a-fA-F]{1,4}|([0-9a-fA-F]{1,4}:){1,7}:|([0-9a-fA-F]{1,4}:){1,6}:[0-9a-fA-F]{1,4}|([0-9a-fA-F]{1,4}:){1,5}(:[0-9a-fA-F]{1,4}){1,2}|([0-9a-fA-F]{1,4}:){1,4}(:[0-9a-fA-F]{1,4}){1,3}|([0-a-fA-F]{1,4}:){1,3}(:[0-9a-fA-F]{1,4}){1,4}|([0-9a-fA-F]{1,4}:){1,2}(:[0-9a-fA-F]{1,4}){1,5}|[0-9a-fA-F]{1,4}:((:[0-9a-fA-F]{1,4}){1,6})|:((:[0-9a-fA-F]{1,4}){1,7}|:)|fe80:(:[0-9a-fA-F]{0,4}){0,4}%[0-9a-zA-Z]{1,}|::(ffff(:0{1,4}){0,1}:){0,1}((25[0-5]|(2[0-4]|1{0,1}[0-9]){0,1}[0-9]).){3,3}(25[0-5]|(2[0-4]|1{0,1}[0-9]){0,1}[0-9])|([0-9a-fA-F]{1,4}:){1,4}:((25[0-5]|(2[0-4]|1{0,1}[0-9]){0,1}[0-9]).){3,3}(25[0-5]|(2[0-4]1{0,1}[0-9]){0,1}[0-9]))$') ) then
    self.success := 1;
    self.message := null;
    return;
else
    self.success := 0;
    self.message := 'Invalid IPv6 address. Example of a valid format: 2001:0db8:0000:0000:0000:ff00:0042:8329';
    return;
end if;

限制为512( https://stackoverflow.com/a/2694119/3112803 )，我我在657.我想不出什么办法将其拆分.

The limit is 512 (https://stackoverflow.com/a/2694119/3112803), I'm at 657. I cannot think of any way to split this up.

将Java类导入Oracle是唯一的方法吗? https://community.oracle.com/thread/1149462?start= 0& tstart = 0

Is importing a java class into Oracle the only way? https://community.oracle.com/thread/1149462?start=0&tstart=0

更新:我正在尝试此操作，但是当我运行select对其进行测试时，它会抛出ORA-29531: no method isProperIPv6Address in class ipv6.我以前没有在Oracle中弄过Java，所以不知道我是否已经关闭或这不是一个好主意. (摘自 https://community.oracle.com/message/8648095 )

UPDATE: I'm trying this but when I run the select to test it, it throws ORA-29531: no method isProperIPv6Address in class ipv6. I haven't messed with java in Oracle before so I'm not sure if I'm close or if this is a bad idea. (taken from https://community.oracle.com/message/8648095)

CREATE OR REPLACE AND RESOLVE JAVA SOURCE NAMED ipv6 as
public class ipv6
{
    public static int isProperIPv6Address(String address)
    {
        try
        {
            java.net.Inet6Address.getByName(address);
            return 1;
        } catch(Exception e) { return 0; }
    }
}

create or replace function isProperIPv6Address (string in varchar2)
return number as language java name 'ipv6.isProperIPv6Address(java.lang.Int) return java.lang.Int';

select isProperIPv6Address('blah') from dual;

看来java.net.Inet6Address.getByName()确实会上网，看看该地址是否确实存在.我理解正确吗?我不需要那个我只需要验证它们的语法是否有效即可.

It does appear that java.net.Inet6Address.getByName() will literally go out to the internet and see if this address really exists. Am I understanding that correctly? I don't need that. I just need to verify that they syntax is valid.

推荐答案

用许多短正则表达式的逻辑或代替长的正则表达式^regexp1|regexp2|...$:
if ( REGEXP_LIKE(v,'^regexp1$') OR REGEXP_LIKE(v,'^regexp2$') OR ... ) then

Replace your long regexp ^regexp1|regexp2|...$ with logical OR of many short regexps:
if ( REGEXP_LIKE(v,'^regexp1$') OR REGEXP_LIKE(v,'^regexp2$') OR ... ) then

更新:

CREATE OR REPLACE AND RESOLVE JAVA SOURCE NAMED ipv6 as
import java.net.Inet6Address;
public class ipv6
...
create or replace function isProperIPv6Address (string varchar2) return number 
as language java name 'ipv6.isProperIPv6Address(java.lang.String) return int';

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