int *转换为常数数组 [英] int* to Constant Array

问题描述

我问了这个问题:等效于裸字符串的数组

不能为const int*提供此功能.真令人失望.所以我的问题是:在实践中，我如何解决这个限制?

To which the answer was C++ doesn't provide this functionality for const int*s. Which is disappointing. So my question then is: In practice how do I get around this limitation?

我想写一个这样的结构:

I want to write a struct like this:

struct foo{
    const char* letters = "abc";
    const int* numbers = ???
};

我不能:

1. &{1, 2, 3}因为我不能使用r值的地址
2. array<int, 3>{{1, 2, 3}}.data()导致初始化后立即清理内存
3. const int* bar(){ return new int[3]{1, 2, 3}; }不会导致删除该指针

1. &{1, 2, 3} cause I can't take the address of an r-value
2. array<int, 3>{{1, 2, 3}}.data() cause the memory is cleaned up immediately after initialization
3. const int* bar(){ return new int[3]{1, 2, 3}; } cause nothing will delete this pointer

我知道我可以使用自动指针解决此问题.我并不是在建议struct foo是好的代码，我试图说明编译器已准备好将const数组"abc"存储在内存中，并在程序退出时进行清理，我希望有一种方法也适用于int.

I know that I can use an auto pointer to get around this. I am not suggesting that struct foo is good code, I am trying to illustrate that the compiler makes a provision to store the const array "abc" in memory and clean it up on program exit, I want there to be a way to do that for ints as well.

有没有办法做到这一点?

Is there a way to accomplish this?

推荐答案

您指向的静态代码怎么样-我认为无论如何编译器内部都会为"strings literals"做些什么?

How about a static which you point to - I think this what the compiler pretty much does internally for "strings literals" anyway?

static const int Numbers[] = {1, 2, 3};

struct foo{
    const char* letters = "abc";
    const int* numbers = Numbers;
};

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