无法接收共享图像-Android 6.0 [英] Unable to receive share image - Android 6.0

查看:165
本文介绍了无法接收共享图像-Android 6.0的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用 aFileChooser 即可在我的应用程序中获取共享图像。画廊中的图像可以正常工作,但是如果我在Google Chrome中使用图像说并尝试共享它,那么我的 imagePath 为null会给我NPE。

I am using the code provided by aFileChooser to get able to get the shared image inside my application. Images from the gallery work OK but if i use an image say inside Google Chrome and try to share it, it gives me a NPE as my imagePath is null.

String imagePath = getPath(getActivity(), imageUri);

我的 uri 被标识为MediaStore(并且),通常从以下代码中获取:

My uri is identified as MediaStore (and) general from this code:

else if ("content".equalsIgnoreCase(uri.getScheme())) {

        if (isGooglePhotosUri(uri))
            return uri.getLastPathSegment();

        return getDataColumn(context, uri, null, null);
    }

但是在 getDataColumn()我的光标转储如下:

However inside getDataColumn() my cursor dump is as follows:

08-24 12:00:58.196  13186    13256    ReceivePhotos  D  Cursor is: >>>>> Dumping cursor android.content.ContentResolver$CursorWrapperInner@e110803
08-24 12:00:58.196  13186    13256    ReceivePhotos  D  0 {
08-24 12:00:58.196  13186    13256    ReceivePhotos  D  _data=null
08-24 12:00:58.196  13186    13256    ReceivePhotos  D  }
08-24 12:00:58.196  13186    13256    ReceivePhotos  D  <<<<<
08-24 12:00:58.196  13186    13256    ReceivePhotos  D  Cursor column index is: 0

getDataColumn()方法:

public static String getDataColumn(Context context, Uri uri, String selection, String[] selectionArgs) {

    Cursor cursor = null;
    final String column = "_data";
    final String[] projection = {
        column
    };

    try {
        cursor = context.getContentResolver().query(uri, projection, selection, selectionArgs,null);
        Log.d("ReceivePhotos", " Cursor is: " + DatabaseUtils.dumpCursorToString(cursor));

        if (cursor != null && cursor.moveToFirst()) {
            final int column_index = cursor.getColumnIndexOrThrow(column);
            Log.d("ReceivePhotos", " Cursor column index is: " + column_index);
            return cursor.getString(column_index);
        }
    } finally {
        if (cursor != null)
            cursor.close();
    }

    return null;
}

ImageUri日志

08-24 12:07:32.780  13629    13696    ReceivePhotos  D  Image uri: content://com.android.chrome.FileProvider/images/screenshot/1472011649310784004280.jpg

电话&操作系统详细信息

Android 6.0.1上的Sony E5823

Sony E5823 on Android 6.0.1

推荐答案

您不能也不应该尝试获取与URI相对应的基础路径-在大多数情况下,您的应用将永远无法访问该路径本身,而只能通过URI。

You cannot and should not attempt to ever get the underlying path corresponding with a URI - in the vast majority of cases your app will never have access to the path itself, but only through the URI.

值得庆幸的是,您可以直接从URI中获取图像的二进制数据:

Thankfully, you can get the binary data of the image from the URI directly:

InputStream in;
Bitmap bitmap = null;
try {
  in = getContentResolver().openInputStream(imageUri);
  // You could do anything with the InputStream.
  // Here we'll just get the Bitmap at full size
  bitmap = BitmapFactory.decodeStream(in);
} catch (IOException e) {
  // Something went wrong
} finally {
  if (in != null) {
    try {
      in.close();
    } catch (IOException ignored) {}
  }
}
// Now you have a Bitmap.

这篇关于无法接收共享图像-Android 6.0的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆