无法接收共享图像-Android 6.0 [英] Unable to receive share image - Android 6.0
问题描述
我正在使用 aFileChooser 即可在我的应用程序中获取共享图像。画廊中的图像可以正常工作,但是如果我在Google Chrome中使用图像说并尝试共享它,那么我的 imagePath
为null会给我NPE。
I am using the code provided by aFileChooser to get able to get the shared image inside my application. Images from the gallery work OK but if i use an image say inside Google Chrome and try to share it, it gives me a NPE as my imagePath
is null.
String imagePath = getPath(getActivity(), imageUri);
我的 uri
被标识为MediaStore(并且),通常从以下代码中获取:
My uri
is identified as MediaStore (and) general from this code:
else if ("content".equalsIgnoreCase(uri.getScheme())) {
if (isGooglePhotosUri(uri))
return uri.getLastPathSegment();
return getDataColumn(context, uri, null, null);
}
但是在 getDataColumn()$ c $中c>我的光标转储如下:
However inside getDataColumn()
my cursor dump is as follows:
08-24 12:00:58.196 13186 13256 ReceivePhotos D Cursor is: >>>>> Dumping cursor android.content.ContentResolver$CursorWrapperInner@e110803
08-24 12:00:58.196 13186 13256 ReceivePhotos D 0 {
08-24 12:00:58.196 13186 13256 ReceivePhotos D _data=null
08-24 12:00:58.196 13186 13256 ReceivePhotos D }
08-24 12:00:58.196 13186 13256 ReceivePhotos D <<<<<
08-24 12:00:58.196 13186 13256 ReceivePhotos D Cursor column index is: 0
getDataColumn()方法:
public static String getDataColumn(Context context, Uri uri, String selection, String[] selectionArgs) {
Cursor cursor = null;
final String column = "_data";
final String[] projection = {
column
};
try {
cursor = context.getContentResolver().query(uri, projection, selection, selectionArgs,null);
Log.d("ReceivePhotos", " Cursor is: " + DatabaseUtils.dumpCursorToString(cursor));
if (cursor != null && cursor.moveToFirst()) {
final int column_index = cursor.getColumnIndexOrThrow(column);
Log.d("ReceivePhotos", " Cursor column index is: " + column_index);
return cursor.getString(column_index);
}
} finally {
if (cursor != null)
cursor.close();
}
return null;
}
ImageUri日志
08-24 12:07:32.780 13629 13696 ReceivePhotos D Image uri: content://com.android.chrome.FileProvider/images/screenshot/1472011649310784004280.jpg
电话&操作系统详细信息
Android 6.0.1上的Sony E5823
Sony E5823 on Android 6.0.1
推荐答案
您不能也不应该尝试获取与URI相对应的基础路径-在大多数情况下,您的应用将永远无法访问该路径本身,而只能通过URI。
You cannot and should not attempt to ever get the underlying path corresponding with a URI - in the vast majority of cases your app will never have access to the path itself, but only through the URI.
值得庆幸的是,您可以直接从URI中获取图像的二进制数据:
Thankfully, you can get the binary data of the image from the URI directly:
InputStream in;
Bitmap bitmap = null;
try {
in = getContentResolver().openInputStream(imageUri);
// You could do anything with the InputStream.
// Here we'll just get the Bitmap at full size
bitmap = BitmapFactory.decodeStream(in);
} catch (IOException e) {
// Something went wrong
} finally {
if (in != null) {
try {
in.close();
} catch (IOException ignored) {}
}
}
// Now you have a Bitmap.
这篇关于无法接收共享图像-Android 6.0的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!