为什么我的FizzBu​​zz代码无法正确输出? [英] Why is my FizzBuzz code not outputting correctly?

问题描述

function counter(numOne, numTwo) {
  for (let i = 0; i <= 100; i++) {

    if (i % numOne === 0) {
      console.log("Fizz");
    }
    if (i % numTwo === 0) {
      console.log("Buzz");
    }
    if (i % numOne === 0 && i % numTwo === 0) {
      console.log("FizzBuzz");
    }
    else if (i <= 100 && i !== i % numOne === 0 || i !== i % numTwo === 0) {
      console.log(i);
    }
  }
}

counter(3, 5);

对于else if循环，它应该console.log所有< = 100 ，但不是 i％numOne === 0 和的数字> i％numTwo === 0 .那么，为什么在输出中仅显示 Fizz ， Buzz 和 FizzBu​​zz ?

For the else if loop, it should console.log all numbers that are <=100, but are not i % numOne === 0 and i % numTwo === 0. So why are only Fizz, Buzz, and FizzBuzz showing up in the output?

推荐答案

好，我不想写一个答案，但是由于您是新来的，所以我将以一种更有意义的方式来说明这一点:

Ok, I didn't want to write an answer but since you're new here, I'll put this in a more meaningful way:

function counter(numOne, numTwo) {
  for (let i = 0; i <= 100; i++) {
    const isFizz = i % numOne === 0
    const isBuzz = i % numTwo === 0

    if (isFizz && isBuzz) {
      console.log("FizzBuzz");
    }
    else if (isFizz) {
      console.log("Fizz");
    }
    else if (isBuzz) {
      console.log("isBuzz")
    }
    else {
      console.log(i);
    }
  }
}

counter(3, 5);

在您的示例中，您有:

i !== i % numOne === 0

如上所述，这里有两个问题:

as stated above, there are two issues here:

1. i！== i 永远不能为 true ，它的值相同，始终为 i === i 或您的情况错误
2. 由于上述错误，因此您将具有以下数学公式: false％numOne 这将导致 NaN ，并且 NaN不等于0

1. i !== i can never be true, it's the same value, it's always i === i or in your case false
2. Since the above is false, you'll have a math equation of: false % numOne this will result in a NaN and NaN does not equal 0

希望如此，以上评论有助于理解您的问题

Hope this and the comments above helps understand your issue

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