这个语法有什么问题? (ANTLRWorks 1.4) [英] What is wrong with this grammar? (ANTLRWorks 1.4)

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问题描述

我用ANTLRWorks 1.4编写了以下代码

I have the following code written in ANTLRWorks 1.4

grammar hmm;

s           :   (put_a_in_b)|(put_out_a)|(drop_kick)|(drop_a)|(put_on_a);

put_a_in_b  :   (PUT_SYN)(ID)(IN_SYN)(ID);  
put_out_a   :   (PUT2_SYN)(OUT_SYN)(ID) | (E1)(ID); 
drop_kick   :   ('drop')('kick')(ID);
drop_a      :   (DROP_SYN)(ID);
put_on_a    :   (E2)(ID);

PUT_SYN     :   'put' | 'place' | 'drop';
PUT2_SYN    :   'put' | 'douse';
IN_SYN      :   'in' | 'into' | 'inside' | 'within';    
OUT_SYN     :   'out';
E1          :   'extinguish'|'douse';
DROP_SYN    :   'drop' | 'throw' | 'relinquish';
WS          :   ( ' '  | '\t' | '\r' | '\n' ) {$channel=HIDDEN;};
ID          :   ('a'..'z'|'A'..'Z'|'_') ('a'..'z'|'A'..'Z'|'0'..'9'|'_')*;
E2          :   'put on'|'don'|'wear';
COMMENT
    :   '//' ~('\n'|'\r')* '\r'? '\n' {$channel=HIDDEN;}
    |   '/*' ( options {greedy=false;} : . )* '*/' {$channel=HIDDEN;}
    ;

当我用输入运行它时:

drop object

我收到了MismatchedTokenException(5!= 15).

I get a MismatchedTokenException(5 != 15).

并输入:

put o1 in o2

我收到一个NoViableAltException.

I get a NoViableAltException.

尽管可以正常运行

place o2 in o2

我对此并不陌生,但似乎有歧义吗?也许我对ANTLR的使用不正确?

I'm new to this, but it seems like there's ambiguities? Or maybe my usage of ANTLR is incorrect?

推荐答案

您已将'drop''put'放入了两个不同的词法规则:

You've put 'drop' and 'put' in two different lexer-rules:

PUT_SYN  : 'put' | 'place' | 'drop';          // drop & put
PUT2_SYN : 'put' | 'douse';                   //        put
...
DROP_SYN : 'drop' | 'throw' | 'relinquish';   // drop

当词法分析器遇到put时,PUT_SYN将始终是与之匹配的规则,因此'put'可以(或应该)从PUT2_SYN规则中删除.

When put is encountered by the lexer, PUT_SYN will always be the rule that matches it, so 'put' could (or should) be removed from the PUT2_SYN rule.

因此,您在解析字符串drop object时遇到的问题:解析器将尝试匹配drop_a : (DROP_SYN)(ID);,但是在词法分析器规则PUT_SYN中将匹配"drop".

So, your problem with parsing the string drop object: the parser will try to match drop_a : (DROP_SYN)(ID); but the "drop" will be matched in the lexer rule PUT_SYN.

编辑

可以更好地将这些同义词列表设置为解析器规则(而不是词法规则).这是一个小演示:

Those synonym-lists can be better made into parser rules (instead of lexer-rules). Here's a small demo:

grammar TextAdventure;

parse
  :  command (EndCommand command)* EOF
  ;

command
  :  put_syn_1 OtherWord in_syn OtherWord
  |  put_syn_2 out_syn_1 OtherWord
  |  out_syn_2 OtherWord
  |  Drop Kick OtherWord
  |  drop_syn OtherWord
  ;

drop_syn
  :  Drop
  |  Throw 
  |  Relinquish
  ;

in_syn
  :  In
  |  Into
  |  Inside
  |  Within
  ; 

put_syn_1
  :  Put
  |  Place
  |  Drop
  ;

put_syn_2
  :  Put
  |  Douse
  ;

out_syn_1
  :  Out
  ;

out_syn_2
  :  Extinguish
  |  Douse
  ;

Space      : (' ' | '\t' | '\r' | '\n'){$channel=HIDDEN;};
EndCommand : ';';
Put        : 'put';
Place      : 'place';
Drop       : 'drop';
Douse      : 'douse';
In         : 'in';
Into       : 'into';
Inside     : 'inside';
Within     : 'within';    
Out        : 'out';
Extinguish : 'extinguish';
Throw      : 'throw';
Relinquish : 'relinquish';
Kick       : 'kick';
OtherWord  : ('a'..'z' | 'A'..'Z')+;

解释以下来源时:

drop object ; put yourself in myshoes ; place it in avase

您将看到ANTLRWorks生成以下解析树:

you'll see ANTLRWorks generate the following parse-tree:

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