用spacy找到名词块的根的POS [英] finding the POS of the root of a noun_chunk with spacy

问题描述

使用spacy时，您可以轻松地在文本的名词短语之间循环，如下所示:

When using spacy you can easily loop across the noun_phrases of a text as follows:

S='This is an example sentence that should include several parts and also make clear that studying Natural language Processing is not difficult'
nlp = spacy.load('en_core_web_sm')
doc = nlp(S)

[chunk.text for chunk in doc.noun_chunks]
# = ['an example sentence', 'several parts', 'Natural language Processing']

您还可以获取名词块的根":

You can also get the "root" of the noun chunk:

[chunk.root.text for chunk in doc.noun_chunks]
# = ['sentence', 'parts', 'Processing']

如何获取所有这些单词的POS(即使看起来名词的短语的根始终是一个名词)，又如何获得该单词的引数，形状和单词的单数形式.

How can I get the POS of every of those words (even if looks like the root of a noun_phrase is always a noun), and how can I get the lemma, the shape and the word in singular of that particular word.

那有可能吗?

thx.

推荐答案

每个chunk.root是令牌，您可以在其中获得不同的属性，包括lemma_和pos_(如果喜欢PennTreekbak POS标签，则可以选择tag_).

Each chunk.root is a Token where you can get different attributes including lemma_ and pos_ (or tag_ if you prefer the PennTreekbak POS tags).

import spacy
S='This is an example sentence that should include several parts and also make ' \
  'clear that studying Natural language Processing is not difficult'
nlp = spacy.load('en_core_web_sm')
doc = nlp(S)
for chunk in doc.noun_chunks:
    print('%-12s %-6s  %s' % (chunk.root.text, chunk.root.pos_, chunk.root.lemma_))

sentence     NOUN    sentence
parts        NOUN    part
Processing   NOUN    processing

BTW ...在这句话中，"processing"是一个名词，所以它的引理是"processing"，而不是"process"，这是动词"processing"的引理.

BTW... In this sentence "processing" is a noun so the lemma of it is "processing", not "process" which is the lemma of the verb "processing".

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