使用Spring处理REST应用程序中映射的模棱两可的处理程序方法 [英] Handling ambiguous handler methods mapped in REST application with Spring

问题描述

我尝试使用如下代码:

@RequestMapping(value = "/{id}", method = RequestMethod.GET)
public Brand getBrand(@PathVariable Integer id) {
    return brandService.getOne(id);
}

@RequestMapping(value = "/{name}", method = RequestMethod.GET)
public List<Brand> getBrand(@PathVariable String name) {
    return brandService.getSome(name);
}

但是我遇到这样的错误，我该怎么办?

But I got error like this, how can I do?

java.lang.IllegalStateException: Ambiguous handler methods mapped for HTTP path 'http://localhost:8080/api/brand/1': {public java.util.List com.zangland.controller.BrandController.getBrand(java.lang.String), public com.zangland.entity.Brand com.zangland.controller.BrandController.getBrand(java.lang.Integer)}
at org.springframework.web.servlet.handler.AbstractHandlerMethodMapping.lookupHandlerMethod(AbstractHandlerMethodMapping.java:375) ~[spring-webmvc-4.2.4.RELEASE.jar:4.2.4.RELEASE]

推荐答案

由于映射不明确，Spring无法区分请求GET http://localhost:8080/api/brand/1是由getBrand(Integer)还是由getBrand(String)处理.

Spring can't distinguish if the request GET http://localhost:8080/api/brand/1 will be handled by getBrand(Integer) or by getBrand(String) because your mapping is ambiguous.

尝试对getBrand(String)方法使用查询参数.似乎更合适，因为您正在执行查询:

Try using a query parameter for the getBrand(String) method. It seems more appropriate, since you are performing a query:

@RequestMapping(value = "/{id}", method = RequestMethod.GET)
public Brand getBrand(@PathVariable Integer id) {
    return brandService.getOne(id);
}

@RequestMapping(method = RequestMethod.GET)
public List<Brand> getBrand(@RequestParam(value="name") String name) {
    return brandService.getSome(name);
}

使用上述方法:

• GET http://localhost:8080/api/brand/1之类的请求将由getBrand(Integer)处理.
• GET http://localhost:8080/api/brand?name=nike之类的请求将由getBrand(String)处理.

• Requests like GET http://localhost:8080/api/brand/1 will be handled by getBrand(Integer).
• Requests like GET http://localhost:8080/api/brand?name=nike will be handled by getBrand(String).

只是一个提示:通常的做法是，在资源集合中首选复数名词.因此，请使用/brands代替/brand.

Just a hint: As a common practice, prefer plural nouns for collections of resources. So instead of /brand, use /brands.

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