Qt:在使用foreach宏进行迭代时，是否可以删除QList元素? [英] Qt: is removing QList elements while iterating using foreach macro possible?

问题描述

我是Qt的新手，正在尝试学习习语.

I'm new to Qt and trying to learn the idioms.

foreach文档说:

当Qt进入foreach循环时，它会自动获取该容器的副本.如果您在迭代时修改容器，则不会影响循环.

Qt automatically takes a copy of the container when it enters a foreach loop. If you modify the container as you are iterating, that won't affect the loop.

但是并没有说如何在用foreach进行迭代时删除元素.我最好的猜测是这样的:

But it doesn't say how to remove an element while iterating with foreach. My best guess is something like:

int idx = 0;
foreach (const Foo &foo, fooList) {
  if (bad(foo)) {
    fooList.removeAt(idx);
  }
  ++idx;
}

似乎必须将idx的范围限制在循环之外(并且必须维护一个单独的循环计数器).

Seems ugly to have to scope idx outside the loop (and to have to maintain a separate loop counter at all).

另外，我知道foreach会复制QList，这很便宜，但是一旦删除元素，会发生什么-还是便宜或有昂贵的复制本-修改正在进行吗?是，发生深拷贝.

Also, I know that foreach makes a copy of the QList, which is cheap, but what happens once I remove an element -- is that still cheap or is there an expensive copy-on-modify going on? Yes, deep copy happens.

这也不像是惯用的Qt.

EDIT : This doesn't seem like idiomatic Qt either.

for (int idx = 0; idx < fooList.size(); ) {
  const Foo &foo = fooList[idx];
  if (bad(foo)) {
    fooList.removeAt(idx);
  }
  else ++idx;
}

推荐答案

您最好为此使用迭代器:

// Remove all odd numbers from a QList<int> 
QMutableListIterator<int> i(list);
while (i.hasNext()) {
    if (i.next() % 2 != 0)
        i.remove();
}

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