将Unicode代码点数组转换为字符串 [英] Convert array of unicode code points to string

问题描述

给出一个表示unicode代码点的字符串数组:

Given an array of strings that represent unicode code points:

let arr : [String] = ["0023", "FE0F", "20E3"]

如何将其动态转换为快捷字符串?静态地，我发现我可以写:

How can I dynamically convert this into a swift string? Statically, I have found I can write:

let str = "\u{0023}\u{FE0F}\u{20E3}"

但是，我想动态地执行此操作，因为每个数组将表示一些代码点序列.在上面的示例中，输出为#️⃣

However, I would like to do this dynamically as each array will represent some sequence of code points. In the above example, the output would be #️⃣

推荐答案

您可以将每个六进制字符串转换为UInt32，为每个元素初始化一个Unicode.Scalar，并从中创建一个String UnicodeScalarView:

You can convert each of your hexa string to UInt32, initialise an Unicode.Scalar for each element and create a String UnicodeScalarView from it:

let arr = ["0023", "FE0F", "20E3"]
let values = arr.compactMap{ UInt32($0, radix: 16) }
let unicodeScalars = values.compactMap(Unicode.Scalar.init)
let string = String(String.UnicodeScalarView(unicodeScalars))

---

这也可以写成一个衬里:

---

Which can be also be written as a one liner:

let arr = ["0023", "FE0F", "20E3"]
let string = String(String.UnicodeScalarView(arr.compactMap{ UInt32($0, radix: 16) }.compactMap(Unicode.Scalar.init)))

编辑/更新:

如果所有字符串都可以用UInt16值表示，则也可以使用字符串初始化程序init(utf16CodeUnits: UnsafePointer<unichar>, count: Int)，如@MartinR 此处:

If all your strings can be represented by UInt16 values you can also use String initializer init(utf16CodeUnits: UnsafePointer<unichar>, count: Int)as shown by @MartinR here:

let arr = ["0023", "FE0F", "20E3"]
let values = arr.compactMap { UInt16($0, radix: 16) }
let string = String(utf16CodeUnits: values, count: values.count)  // "#️⃣"

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