将类型变量传递给函数 [英] Passing in a type variable into function

问题描述

我试图通过将类型传入函数来实现类型断言.换句话说，我正在尝试实现以下目标:

I'm trying to achieve a type assertion by passing in a type into a function. In other words, I'm trying to achieve something like this:

// Note that this is pseudocode, because Type isn't the valid thing to use here
func myfunction(mystring string, mytype Type) {
    ...

    someInterface := translate(mystring)
    object, ok := someInterface.(mytype)

    ...  // Do other stuff
}

func main() {
    // What I want the function to be like
    myfunction("hello world", map[string]string)
}

要在myfunction中成功执行类型断言，我需要在myfunction中使用什么正确的函数声明?

What's the proper function declaration I need to use in myfunction, to successfully perform the type assertion in myfunction?

推荐答案

@ hlin117，

@hlin117,

嘿，如果我正确理解了您的问题，并且需要比较类型，请按照以下步骤操作:

Hey, if I understood your question correctly and you need to compare the types, here's what you can do:

package main

import (
    "fmt"
    "reflect"
)

func myfunction(v interface{}, mytype interface{}) bool {
    return reflect.TypeOf(v) == reflect.TypeOf(mytype)
}

func main() {

    assertNoMatch := myfunction("hello world", map[string]string{})

    fmt.Printf("%+v\n", assertNoMatch)

    assertMatch := myfunction("hello world", "stringSample")

    fmt.Printf("%+v\n", assertMatch)

}

方法是使用您要匹配的类型的样本.

The approach is to use a sample of the type you'd like to match.

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