Apache将所有重定向到index.php，现有文件和文件夹除外 [英] Apache redirect all to index.php except for existing files and folders

问题描述

我有index.php通过$_SERVER[‘REQUEST_URI’]变量读取完整路径.我的任务是当用户输入以下内容时:www.domain/resource/777使用路径/resource/777重定向到index.php并解析$_SERVER[‘REQUEST_URI’]以执行一些逻辑.但是我也有真实的文件和文件夹，例如:

I have index.php that reads full path by $_SERVER[‘REQUEST_URI’] variable. My task is when user enter: www.domain/resource/777 redirect to index.php with path /resource/777 and parse $_SERVER[‘REQUEST_URI’] to do some logic. But I have also real files and folders like:

• css/theme.css
• assets/assets.js
• resource/locale.js

当我尝试此配置时:

RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME} !-f
RewriteRule ^(.*)$ /index.php [L]

客户端无法获取所有的css等文件.如何在Apache中编写正确的规则以实现这一目标?

Client could not get all css and etc files. How to write correct rule in Apache to achive this?

推荐答案

如果您使用的是Apache 2.2.16或更高版本，则可以用一个指令完全替换重写规则:

If you are using Apache 2.2.16 or later, you can replace rewrite rules entirely with one single directive:

FallbackResource /index.php

请参见 https://httpd.apache.org/docs/2.2/mod/mod_dir.html#fallbackresource

基本上，如果请求将导致错误404，则将使用后备资源uri代替该请求，以正确填充$_SERVER[‘REQUEST_URI’]变量.

Basically, if a request were to cause an error 404, the fallback resource uri will be used to handle the request instead, correctly populating the $_SERVER[‘REQUEST_URI’] variable.

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