AT + CUSD命令标准响应 [英] AT+CUSD command standard response
问题描述
For those interested in background of this question, Please see this question
我的问题:
我发现了一个新的GSM调制解调器( Wavecom Q24 ),它对AT+CUSD
命令做出了以下响应:
I found a new GSM modem (Wavecom Q24) which does the following in response to AT+CUSD
command:
返回中间OK
响应. 2或3秒钟后(ussd命令中的正常网络延迟),它会给出实际的响应.这是标准行为吗?
Returns an intermediate OK
response. After 2 or 3 seconds(the normal network delay in ussd commands) it gives the actual response. Is this standard behaviour?
推荐答案
当您放置 AT + CUSD
发送不带任何参数的AT + CUSD表示您正在询问调制解调器是否支持此命令.
Sending AT+CUSD without any parameter mean you are asking the modem if it support this command.
您需要添加更多参数
AT+CUSD=[<n>[,<str>[,<dcs>]]]
例如: 我在多哥,正在使用Togocel SIM卡.要检查我的余额,我必须使用
Eg: I'm in Togo the i'm using Togocel SIM card. To check my balance i must use
AT+CUSD=1,"*444#",15
< n> :整数类型(设置/显示结果代码的显示状态为 TE) 0禁用向TE显示结果代码 1启用将结果代码呈现给TE 2个取消会话(不适用于读取命令响应)
< n > : integer type (sets/shows the result code presentation status to the TE) 0 disable the result code presentation to the TE 1 enable the result code presentation to the TE 2 cancel session (not applicable to read command response)
< str> :字符串类型USSD字符串(未提供参数时,不会查询网络)
< str > : string type USSD-string (when parameter is not given, network is not interrogated)
< dcs> :整数类型(显示小区广播数据编码方案",请参阅3GPP TS 23.038 [25]).默认值为0.
< dcs > : integer type (shows Cell Broadcast Data Coding Scheme, see 3GPP TS 23.038 [25]). Default value is 0.
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