从文件中读取整数并将其存储在数组C ++中 [英] Reading integers from file and store them in array C++

问题描述

这是我的代码，但是我遇到了第一个数字无限循环

我想从他的文件中读取整数并将它们存储在数组中

this my code but i get infinite loop with the first number
I want to read the integers fromt he file and store them in the array

文件包含：

8 5 12 1 2 7

8 5 12 1 2 7

#include<iostream>
#include<fstream>
#include<string>
using namespace std;

int main()
{    
    int n = 0; //n is the number of the integers in the file ==> 12
    int num;
    int arr[100];

    ifstream File;
    File.open("integers.txt");
    while(!File.eof())
    {
        File >> arr[n];
        n++;
    }

    File.close();

    for(int i=0;i<12;n++)
    {
        cout << arr[i] << " ";
    }

    cout << "done\n";
    return 0;
}

请帮助

推荐答案

我同意@ravi，但我为您提供一些提示：

I agree with @ravi but I some notes for you:

如果您不知道其中有多少个整数文件，并且文件仅包含 个整数，您可以执行以下操作：

If you don't know how many integers are in the file and the file contains only integers, you can do this:

std::vector<int>numbers;
int number;
while(InFile >> number)
    numbers.push_back(number);

您需要＃include< vector>

最好先读取文件中有多少个整数，然后使用循环读取它们：

it would be better if you read how many integers are in the file and then use loop to read them:

int count;
InFile >> count;
int numbers[count];       //allowed since C++11

for(int a = 0; a < count; a++)
    InFile >> numbers[a];

---

注意：我没有检查成功阅读，但这是一个好习惯。

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