无法使Ajax在CakePHP中工作 [英] Can't get ajax to work in CakePHP
问题描述
我正在尝试在CakePHP 2.3中运行ajax请求。我正在处理此帖子:
简单的ajax示例与cakephp 2.3.0
I am trying to run an ajax request in CakePHP 2.3. I am working off of this post: simple ajax example with cakephp 2.3.0
我无法正常工作,这是我的代码:
I cant get it to work, here is my code:
$("#node-form-save").click(function(){
event.preventDefault();
var firstName = $("#node-form-first-name").val();
var lastName = $("#node-form-last-name").val();
var dob = $("#node-form-dob").val();
$.ajax({
url:'/persons/create',
type: 'GET',
datatype: 'json',
data: {firstName: firstName, lastname: lastName, dob:dob},
success: function(data){
alert("succes");
}
});
$('#modal-pop').jqmHide();
})
我从一个简单的测试开始,看看是否达到了成功功能,但是我没有警报。我的代码有什么问题?网址正确。 url / persons有效,当我输入/ persons / create时,我得到一个CakePHP屏幕,说我没有视图(但是我不想要一个,我在做ajax。
我列出了我的控制器(PersonsController .php)
I started with a simple test, to see if the sucess function is reached, but I get no alert. What is wrong with my code? The url is correct. The url /persons works, and when I type in /persons/create I get a CakePHP screen saying that I have no view (but I don't want one, I am doing ajax. I list my controller (PersonsController.php) below
class PersonsController extends AppController
{
public $helpers = array('html', 'form');
public function index()
{
}
public function create()
{
}
}
现在,这样我就可以使用基本功能。
I left the functions blank for now, just so I can get the basic functionality working.
推荐答案
首先:为什么要获取
您说过您不想要视图,但是您的代码无处指定该视图。对于ajax,为避免呈现视图和布局,请执行以下操作
You said you don't want a view, but your code nowhere specifies that. For ajax, and to avoid rendering the view and the layout, do this
public function create() {
$this->autoRender = false;
}
此外,如果这样做,您将无法获得任何回报,因此在操作中,您需要回显值,以便ajax可以接收它。
Also, if you do that, you won't get anything in return, so in the action, you need to echo the values so ajax can recieve it.
提示,您可以通过简单的检查将要使用ajax执行的功能和正常方式分开
And a tip, you can separate the functions you want to excecute with ajax and the normal way with a simple check
public function create() {
if( $this->request->is('ajax') ) {
$this->autoRender = false;
echo 'hello result';
return;
}
//else, handle this action as a normal one and render a view and whatever
}
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