在c中将2个字符加在一起的问题 [英] problems adding 2 characters together in c
问题描述
我目前正在尝试在c中添加2个字符,即
I'm currently trying to add 2 characters in c i.e.
char a = 127;
char b = 127;
char c = a + b;
printf("%d\n", c);
打印出4294967278,我每次将两个数字相加而得到的ASCII码时实际上都遇到了问题值将大于127,这是怎么回事?字符不是8位还是256个可能的数字?
which prints out 4294967278, I'm actually having problems anytime I add 2 numbers together where the resultant ASCII value would be greater than 127, what is happening here? aren't characters 8 bits or 256 possible numbers? so adding values that would be less than 256 should work no?
推荐答案
可能是因为您的 char
是签名的
,可以保存-128到127之间的值。通过使用
Probably because your char
s are signed
and can hold values from -128 to 127. By using
char c = a + b;
您有一个溢出的签名字符
导致未定义行为。您可以使用 unsigned char
来解决此问题:
you have an overflow and overflow of signed char
results in Undefined Behavior. You can use an unsigned char
to get rid of the problem:
unsigned char c = a + b;
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