将时间转换为浮点数 [英] Converting time to a float

问题描述

我编写了一个程序来计算工作时间，但最后，它返回的值是时间。

I wrote a program to compute the hours I've worked but at the end, it returns the value as a time.

例如：我从11岁开始工作： 45至4:30。
我的程序返回4:45我希望它返回4.75。

EX: I worked from 11:45 to 4:30. My program returns 4:45 I would like it to return 4.75.

我如何转换它？

我正在使用以下代码：

import datetime as dt

from datetime import timedelta

start =(input("Enter start time: " ))
end =(input("Enter start time: " ))
start_dt = dt.datetime.strptime(start, '%H:%M')
end_dt = dt.datetime.strptime(end, '%H:%M')
time =(end_dt - start_dt)
if time.days < 0:
    time=timedelta(days=0,seconds=time.seconds,microseconds=time.microseconds)
    time= str(time)
    time2=dt.datetime.strptime(time, '%H:%M:%S') 
    off_set=dt.datetime.strptime('12:00:00', '%H:%M:%S')
    time= time2 - off_set 

print (time)

推荐答案

如果您使用日期时间，则小时和分钟方法应该可以为您提供所需的信息

If you use a datetime, the hour and minute method should give you what you want

>>>a=datetime.datetime.now().time()
>>>a
datetime.time(21, 17, 35, 562000) 
>>>a.hour+a.minute/60.0
21.283333333333335

如果您使用时间增量（如在您的代码中就是这种情况），您应该使用：

If you are using a timedelta (as is the case in your code), you should use :

mytimedelta = atime - anothertime
secs=mytimedelta.seconds #timedelta has everything below the day level stored in seconds
minutes = ((secs/60)%60)/60.0
hours = secs/3600
print hours + minutes

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