XML反序列化:将缺少的元素反序列化为null属性值 [英] XML deserialization: Deserialize missing element into null property value
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问题描述
我的xml文档具有一个可以包含多个子元素的元素。在我的课程中,我将该属性声明为:
My xml document has a element that can contains multiple child elements. In my class, I declare the property as:
[XmlArray("files", IsNullable = true)]
[XmlArrayItem("file", IsNullable = false)]
public List<File> Files { get; set; }
反序列化期间,如果< files>
元素丢失,我希望Files属性为 null 。但是,发生的是将文件反序列化为空的List对象。我该如何预防?
During deserialization, if the <files>
element is missing, I want the Files property to be null. However, what happens is that Files is deserialized into an empty List object. How do I prevent that?
推荐答案
实现此目的的一种方法是封装列表:
One option that achieves that is encapsulation of the list:
public class Foo
{
[XmlElement("files", IsNullable = true)]
public FooFiles Files { get; set; }
}
public class FooFiles
{
[XmlElement("file", IsNullable = false)]
public List<File> Files { get; set; }
}
此处, Foo.Files $ c如果没有
< files />
元素,则$ c>将为 null
。
Here, Foo.Files
will be null
if there is no <files/>
element.
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