emgu在图像b中找到图像a [英] emgu finding image a in image b

问题描述

我是emgu的新手，想从何处入手一些建议。

I'm new to emgu and would like some advice on where to start.

我看过形状检测，但是对于我来说它太复杂了需要..我认为..和我的surfexample无法正常工作。我收到此错误：

I've looked through the shape detection but its far too complex for what i need .. i think.. and my surfexample isn't working. I get this error:

无法在EMGU.CV中使SURF示例正常工作吗？

无论如何，这就是我想做的事情：查找图像A图像A是一个简单的正方形，它始终具有相同的1个像素灰色边框，并且始终具有相同的大小（我相信），但是内部颜色可以是黑色或大约7种其他颜色中的一种（只能是纯色）。当我按下按钮时，我需要在图像b中找到图像A的坐标。参见下面的图像。

Anyway, this is what i would like to do: Find image A in image B. Image A is a simple square which always has the same grey 1 pixel border and always the same size (i believe) but the inner colour could be black or one of about 7 other colours (only ever a solid colour). i need to find the coordinates of image A in image b when i press a button. see the below images.

图像 B

并且

图片 A

< img src = https://i.stack.imgur.com/HJ29C.png alt =图像a>

推荐答案

鸡皮答案是正确的，但我认为编写一些代码也可能会有所帮助。这是我的代码，使用 MatchTemplate 检测源图像（图像B）中的模板（图像A）。正如 Goosebumps 所指出的那样，您可能希望在模板周围包括一些灰色。

Goosebumps answer is correct, but I thought that a bit of code might be helpful also. This is my code using MatchTemplate to detect a template (image A) inside a source image (image B). As Goosebumps noted, you probably want to include some grey around the template.

Image<Bgr, byte> source = new Image<Bgr, byte>(filepathB); // Image B
Image<Bgr, byte> template = new Image<Bgr, byte>(filepathA); // Image A
Image<Bgr, byte> imageToShow = source.Copy();

using (Image<Gray, float> result = source.MatchTemplate(template, Emgu.CV.CvEnum.TM_TYPE.CV_TM_CCOEFF_NORMED))
{
    double[] minValues, maxValues;
    Point[] minLocations, maxLocations;
    result.MinMax(out minValues, out maxValues, out minLocations, out maxLocations);

    // You can try different values of the threshold. I guess somewhere between 0.75 and 0.95 would be good.
    if (maxValues[0] > 0.9)
    {
        // This is a match. Do something with it, for example draw a rectangle around it.
        Rectangle match = new Rectangle(maxLocations[0], template.Size);
        imageToShow.Draw(match, new Bgr(Color.Red), 3);
    }
}

// Show imageToShow in an ImageBox (here assumed to be called imageBox1)
imageBox1.Image = imageToShow;

这篇关于emgu在图像b中找到图像a的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！