二维数组的总和 [英] Sum of a two dimensional array

问题描述

我有这个2D数组L(i，j).如何求和所有取决于i的元素，并将结果作为j

I have this 2D array L(i,j). How can I sum all the elements depending of i and make the result as a function of j

我做到了:

 do j=1,10
  do i =1,30
   T(j) = Sum( L(:,j)
  end do 
 end do

可以吗?

推荐答案

几乎...您不使用i(并且不需要)，并且缺少一个括号:

Almost... you don't use i (and you don't need to), and you are missing one bracket:

do j=1,10
  T(j) = Sum( L(:,j) )
enddo ! j

您还可以在 sum 中使用维度参数来执行此操作一行操作:

You could also use the dimension parameter in sum to do this operation in one line:

T = sum( L, dim=1 )

但是，我发现它很难阅读并且会坚持使用循环-在性能方面不应该有所不同.

However, I find that very difficult to read and would stick with the loop - it shouldn't make a difference in terms of performance.

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