Python Glob和方括号字符('[]') [英] Python glob and bracket characters ('[]')

问题描述

/Users/smcho/Desktop/bracket/[10,20]目录具有"abc.txt"，但是当我运行此Python代码时

/Users/smcho/Desktop/bracket/[10,20] directory has "abc.txt", but when I run this Python code

import glob
import os.path

path1 = "/Users/smcho/Desktop/bracket/\[10,20\]"
pathName = os.path.join(path1, "*.txt")
print glob.glob(pathName)

它返回一个空列表.

• Python的glob无法处理括号或其他字母吗?
• 有什么办法解决这个问题?

推荐答案

glob中的括号用于字符类(例如，[a-z]将匹配小写字母).您可以将每个括号放在一个字符类中以强制将它们匹配:

The brackets in glob are used for character classes (e.g. [a-z] will match lowercase letters). You can put each bracket in a character class to force them being matched:

path1 = "/Users/smcho/Desktop/bracket/[[]10,20[]]"

[[]是仅包含字符[的字符类，而[]]是仅包含字符]的字符类(可以将闭括号放在字符类中，方法是将其放在第一个字符中位置).

[[] is a character class containing only the character [, and []] is a character class containing only the character ] (the closing bracket can be placed in a character class by putting it in the first position).

此外，由于括号不会在字符串文字中转义，因此您的代码将查找反斜杠以及括号.

Additionally, since brackets aren't escaped in string literals, your code will look for a backslash as well as a bracket.

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