将字符串数组传递给函数C [英] Passing array of strings to functions C

问题描述

我目前对如何将字符串数组传递给函数感到困惑.我创建了一个一维数组.我已经做过的方法有效，但是似乎多余，我认为有更好的方法可以做到这一点，但我不确定如何做.我试图找到一种可以一次将所有4个元素传递给函数的方法.

i am currently confused as to how i can pass an array of strings to a function. I have created a one-dimensional array. The method that i have done works but it seems redundant and i think there is a better way of doing this yet i am unsure how. I am trying to find a way where i can pass all 4 elements to the function at one time.

这是我的代码示例.

#include <stdio.h>
#include <string.h>
#include <ctype.h>

void sort(char *,char *,char *, char *);//Function prototype
int main()
{
    char *string_database[4]={'\0'};
    string_database[0]="Florida";
    string_database[1]="Oregon";
    string_database[2]="California";
    string_database[3]="Georgia";
    sort(string_database[0],string_database[1],string_database[2],string_database[3]);
    return 0;
}

void sort(char *string1, char *string2, char *string3, char *string4)
{

    printf("The string is= %s\n",string1);
    printf("The string is= %s\n",string2);
    printf("The string is= %s\n",string3);
    printf("The string is= %s\n\n\n",string4);

}

预先感谢您，感谢您对我的问题的答复.

Thank you in advance, i appreciate any replies to my problem.

推荐答案

您可以这样做:

void sort(char **, int);
int main()
{
    char *string_database[5]={'\0'};
    string_database[0]="Florida";
    string_database[1]="Oregon";
    string_database[2]="California";
    string_database[3]="Georgia";

    sort(string_database, 4);
    return 0;
}

void sort(char **str, int n)
{
    int i = 0;
    for (i = 0; i < n; i++)
      printf("The string is= %s\n",str[i]);

}

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