比较子字符串数组 [英] Compare arrays of sub-string

问题描述

如何检查字符串数组是否包含存储在另一个字符串数组中的单词的一部分?

How can I check if an array of strings contains part of words stored in another array of strings ?

假设我已经声明了这三个数组:

Let's say I've declared these three arrays :

array1 = ["Lorem", "ipsum", "dolor" "sit" "amet"]

array2 = ["Lorem", "ipsum"]

keywords = ["ipsum", "dol"]

在将 array1 与关键字进行比较时，我想得到类似 true 的东西，因为"ipsum" 和<在将 array2 与 keywords 进行比较时，code>"dol" 位于 array1 中，但 false "dol" 不在 array2

When comparing array1 with keywords, I want to get something like true because "ipsum" and "dol" are in array1, but false, when comparing array2 with keywords because "dol" isn't in array2

我搜索了一个小时，但是我不知道该怎么做...我成功地比较了带有一个关键字而不是多个关键字的数组.

I searched for an hour, but I don't know how to do it... I succeeded to compare arrays with one keyword, but not with several keywords.

推荐答案

• 对于关键字数组中的每个元素(使用 .every())
• 其他数组中必须有一些元素(使用 .some())
• 其中包括当前正在考虑的字符串(使用 .includes())

演示:

let array1   = ["Lorem", "ipsum", "dolor", "sit", "amet"],
    array2   = ["Lorem", "ipsum"],
    keywords = ["ipsum", "dol"];

let compare = (a, k) => k.every(s => a.some(v => v.includes(s)));

console.log(compare(array1, keywords));
console.log(compare(array2, keywords));

文档:

• Array.prototype.every()
• Array.prototype.some()
• String.prototype.include()

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