我如何使用Bash命令计算pi [英] How can I calculate pi using Bash command

问题描述

我正在学习bash脚本.在探索数学函数时，我遇到了一个计算pi值的命令.

  seq -f'4/％g'1 2 99999 |粘贴-sd- + |公元前 

尽管我了解基本seq命令的工作原理，但我无法理解上述命令的工作原理.有人可以说明它是如何工作的吗??

解决方案

这使用Gregory–Leibniz系列计算π的值:

seq -f'4/％g'1 2 99999 生成分数:

  4/14/34/54/74/94/114/134/154/174/19 

粘贴管道 paste -sd-+ 将它们与备用定界符-和 + 结合在一起.

最后， bc -l <​​/code>执行算术运算以得出结果.

---

如

I am learning bash scripting. While exploring the math functions i am came across a command which calculated the value of pi.

seq -f '4/%g' 1 2 99999 | paste -sd-+ | bc -l

Although i understand how the basic seq command works, I am unable to understand how does the above command works. Can anybody please clarify how does it work.?

解决方案

This calculates the value of π using Gregory–Leibniz series:

seq -f '4/%g' 1 2 99999 generates the fractions:

4/1
4/3
4/5
4/7
4/9
4/11
4/13
4/15
4/17
4/19

The paste pipeline paste -sd-+ combines those with alternate delimiters - and +.

Finally, bc -l performs the arithmetic to give the result.

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EDIT: As noted in the comment, this sequence converges very slowly. Machin's formula has a significantly higher rate of convergence:

Using the same expansion for tan^-1(x):

to compute π, we can see that it produces the correct value to 50 digits¹ using just the first 50 terms of the series:

$ { echo -n "scale=50;"; seq 1 2 100 | xargs -n1 -I{} echo '(16*(1/5)^{}/{}-4*(1/239)^{}/{})';} | paste -sd-+ | bc -l
3.14159265358979323846264338327950288419716939937510

With just 100 terms, the value of π is computed accurately to more than 100 digits:

$ { echo -n "scale=100;"; seq 1 2 200 | xargs -n1 -I{} echo '(16*(1/5)^{}/{}-4*(1/239)^{}/{})';} | paste -sd-+ | bc -l
3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679

¹ Pi

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