Windows Batch，如何删除第一行和最后一行并另存为新的文本文件 [英] Windows Batch, how to remove first line and last line and save as a new text file

问题描述

text1.txt

text1.txt

20150716
aaaa
bbbb
cccc
dddd
END

我想删除20150716，然后整个文本将上移1行并删除最后一个特定的字符串"END".最后，另存为名为text1_copy.txt的新文件.然后，文件变为:

I would like to remove 20150716, then the whole text will move up by 1 line and remove the last particular string "END". Finally, save as a new file called text1_copy.txt. Then, file becomes:

aaaa
bbbb
cccc
dddd

有什么想法吗?谢谢.

推荐答案

这只是跳过第一行，而不写最后一行.

This just skips the first line and does not write the last one.

@echo off
    setlocal enableextensions disabledelayedexpansion

    for %%a in ("text1.txt") do > "%%~dpna_copy%%~xa" (
        set "line="
        for /f "skip=1 tokens=* delims=0123456789" %%a in ('
            findstr /n /r "^" "%%a"
        ') do (
            if defined line (
                setlocal enabledelayedexpansion
                echo(!line:~1!
                endlocal
            )
            set "line=%%a"
        )
    )

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