为什么我不能使用间接运算符取消对一个对象的指针,该对象是一个数组元素? [英] Why can't I dereference a pointer to an object that's an array-element using the indirection operator?
本文介绍了为什么我不能使用间接运算符取消对一个对象的指针,该对象是一个数组元素?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
是否不可能使用indirection(dereference)运算符取消对存储在数组中的对象的指针的引用,或者我做错了什么?
Is it not possible to dereference a pointer to an object that's stored in an array using the indirection(dereference) operator or am I doing something wrong?
#include <iostream>
class A {
public:
virtual void test() {
std::cout << "A\n";
}
};
class B : public A {
public:
void test() {
std::cout << "B\n";
}
};
int main() {
A* v[2];
v[0] = new A();
v[1] = new B();
v[0]->test();
*(v[1]).test(); // Error! If the arrow operator is used instead
// though, the code compiles without a problem.
return 0;
}
这是我得到的错误:
$ g++ -std=c++11 test.cpp && ./a.out
test.cpp: In function ‘int main()’:
test.cpp:26:13: error: request for member ‘test’ in ‘v[1]’, which is of
pointer type ‘A*’ (maybe you meant to use ‘->’ ?)
*(v[1]).test();
推荐答案
根据运算符优先级, operator.
(成员访问运算符)的优先级高于 operator *
(间接/取消引用运算符),因此 *(v [1]).test();
等效于 *((v [1]).test());
,这是无效的.(您不能通过 opeartor在
.) v [1]
上的 A *
上调用 test()
.
According to the Operator Precedence, operator.
(member access operator) has higher precedence than operator*
(indirection/dereference operator) , so *(v[1]).test();
is equivalent to *((v[1]).test());
, which is not valid. (You can't call test()
on v[1]
which is A*
via opeartor.
.)
将其更改为
(*v[1]).test();
这篇关于为什么我不能使用间接运算符取消对一个对象的指针,该对象是一个数组元素?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文