如何将CryptoPP :: Integer转换为char * [英] How to convert CryptoPP::Integer to char*

问题描述

我想将myVar从 CryptoPP:Integer 转换为 char * 或String:代码如下:

I want to convert myVar from CryptoPP:Integer to char* or to String : The code is below :

CryptoPP::Integer myVar = pubKey.ApplyFunction(m);
std::cout << "result: " << std::hex << myVar<< std::endl;

我一直在互联网上寻找将 CryptoPP:Integer 转换为 char * 的方法，但是我没有运气.因此，将 CryptoPP:Integer 转换为 char * 真的是所有人的问题，或者我不太了解类型 CryptoPP:Integer 在C ++中.

I have been searching the Internet for converting CryptoPP:Integer to char* but I have had no luck finding. So, either it is really a problem with all to convert CryptoPP:Integer to char*, either I didn't understand very well type CryptoPP:Integer within C++ .

有人可以帮我吗?

推荐答案

除了明确支持<< 以外，不了解 CryptoPP :: Integer 的另一种方法.您的问题所隐含的code>是使用 std :: stringstream :

One way, without knowing much more about CryptoPP::Integer other than it clearly supports << as implied by your question, is to use std::stringstream:

std::stringstream ss;
ss << std::hex /*if required*/ << myVar;

使用例如 std :: string s = ss.str(); 的方法提取基础的 std :: string .然后，只要 s 在范围内，就可以使用 s.c_str()来访问 const char * 缓冲区.调用并依赖 c_str()的结果后，请勿以任何方式更改 s ，因为这样做并随后依赖该结果的行为是未定义.

Extract the underlying std::string using, say std::string s = ss.str();. You can then use s.c_str() to access the const char* buffer for as long as s is in scope. Don't change s in any way once you've called and relied upon the result of c_str() as the behaviour of doing so and subsequently relying on that result is undefined.

有一些更整洁的C ++ 11解决方案，但这需要您(和我)对类型有更多了解.

There are neater C++11 solutions but that requires you (and me) to know more about the type.

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