C ++变量声明被视为函数声明 [英] C++ variable declaration is treated like a function declaration

查看:180
本文介绍了C ++变量声明被视为函数声明的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

这个问题是理论上的,尽管很有趣,是什么使MS VS2010将以下变量声明(在 main 内部)视为函数声明:

The question is fairly theoretical, though it's interesting what makes MS VS2010 treat the following variable declaration (inside main) like a function declaration:

typedef std::shared_ptr<asymm::PrivateKey> PrivateKeyPtr;

...
void main()
{
    ...
    maidsafe::dht::PrivateKeyPtr pk(); // I'm trying to init variable here, though it thinks it's function declaration

    kNode->node()->Store(key, value, "", ttl, pk, std::bind(&StoreCallback, args::_1, key, ttl));
}

它引发以下异常:

Error   5   error C2664: 'maidsafe::dht::Node::Store' : cannot convert parameter 5 from 'maidsafe::dht::PrivateKeyPtr (__cdecl *)(void)' to 'maidsafe::dht::PrivateKeyPtr'  C:\Projects\MaidSafe-DHT\src\maidsafe\dht\demo\demo_main.cc 286 1   KademliaDemo

以下几行就像一个符咒一样:

While the following lines work like a charm:

maidsafe::dht::PrivateKeyPtr pk = maidsafe::dht::PrivateKeyPtr();

kNode->node()->Store(key, value, "", ttl, pk, std::bind(&StoreCallback, args::_1, key, ttl));

推荐答案

不使用()声明它:

maidsafe::dht::PrivateKeyPtr pk;

不幸的是,对于为您提供未初始化值的原始类型,但是在C ++ 11中,您可以使用 {} 进行值初始化:

Unfortunately, for primitive types that gives you an uninitialized value, but in C++11 you can value initialize with {}:

maidsafe::dht::PrivateKeyPtr pk{};

有关相关的解析问题,请参见 c ++最令人讨厌的解析.

For a related parsing issue, see the c++ most vexing parse.

这篇关于C ++变量声明被视为函数声明的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆